The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).
The equation 121b⁴ − 49
To find the Factorization of 121b⁴ − 49.
<h3>
What is the factor of a^2-b^2?</h3>
The factor of a^2-b^2 is (a+b)(a-b)
We have write the given equation in the form of a^2-b^2
Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).
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brainly.com/question/25829061
Answer:
Graph D.
Step-by-step explanation:
The line goes through the origin, and therefore shows direct variation.
Answer:54
Step-by-step explanation:
9+9=18
18+18=36
36+18=54
Hope this helps:)
Answer:
x=65/14
Step-by-step explanation:
(x-10)/(x-4)=50/-6
-50/6=-25/3
(x-10)/(x-4)=-25/3
x-10=-25/3(x-4)
x-10=-25/3x+100/3
x-(-25/3x)=100/3+10
x+25/3x=130/3
28/3x=130/3
x=(130/3)/(28/3)
x=(130/3)(3/28)
x=130/28
x=65/14
Answer:
7^12=13,841,287,201
Step-by-step explanation:
when you are putting a power to a power, you just multiply the powers by each other
