Answer:
Option (C)
Step-by-step explanation:
From the graph attached,
In ΔABC and ΔA'B'C',
∠A ≅ ∠A'
∠B ≅ ∠B'
Therefore, ΔABC ~ ΔA'B'C'
Corresponding sides of these triangles will be proportional.
Therefore, ratio of the sides, AC : A'C' = 1 : 3 shows that image triangle A'B'C' is a dilated form of pre-image ABC with a scale factor of 3.
Option (C) will be the correct option.
Yeeee
assuming your equaiton is
remember some nice log rules
translates to
and
and
and
and
and
if
then a=b
so
we can simplify a bit of stuff here
the
can be simplified to
so we gots now
same base so
times both sides by 5
divide both sides by 2
answer is x=75
Answer: In 12 months they will have the same amount, which will be $520.
Step-by-step explanation:
220 + 25m = 100 + 35m
m = month
Subtract 100 from each side
120 + 25m = 35m
Subtract 25m from each side
120 = 10m
Divide each side by 10
12 = m
Answer:
The volume of the sphere is 288π in³
Step-by-step explanation:
To calculate the volume of a sphere we have to use the following formula:
V = volume
r = radius
V = ⁴⁄₃πr³
V = ⁴⁄₃ * π * (6in)³
V = π * ⁴⁄₃ * 216 in³
V = 288π in³
The volume of the sphere is 288π in³
Because the vertex of the parabola is at (16,0), its equation is of the formy = a(x-10)² + 15
The graph goes through (0,0), thereforea(0 - 10)² + 15 = 0100a = -15a = -0.15
The equation is y = f(x) = -0.15(x - 10)² + 15
The graph is shown below.
Part A
Note that y = f(x).
The x-intercepts identify values where the function or y=0. The x-intercepts occur at x=0 and x=20, or at (0,0) and (20,0).
The maximum value of y occurs at the vertex (10, 15) because the curve is down due to the negative leading coefficient of -0.15.
The curve increases in the interval x = (-∞, 10) and it decreases in the interval x = (10, ∞).
Part B
When x=12, y = -0.15(12 - 10)² + 15 = 14.4When x=15, y = -0.15(15 - 10)² + 15 = 11.25
The average rate of change between x =12 to x = 15 is(11.25 - 14.4)/(15 - 12) = -1.05
This rate of change represents the slope of the secant line from A to B. It approximates the rate at which f(x) decreases in the interval x =[12, 15].
