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andrezito [222]
3 years ago
7

fourteen boys and 21 girls will be equallly divided into groups find the greatest number of groups that cannbe created if no one

is left out
Mathematics
2 answers:
Slav-nsk [51]3 years ago
6 0

The <em><u>correct answer</u></em> is:

If you must have the same number of boys and girls in each group, you can have 7 groups.

Explanation:

To do this, we find the Greatest Common Factor (GCF) of 14 and 21. For this, we find the prime factorization of each number:

14 = 2(7)

21 = 3(7)

The only common factor between these two numbers is 7. Thus we can have 7 groups.

(In each group, we would have 14/7 = 2 boys and 21/7 = 3 girls.)

Irina-Kira [14]3 years ago
4 0
Well if you add 14 and 21 you get 35. with 35 you can have 7 groups of 5 but if they have to be equal with the number of boys and girls in each group it would still be 7. two boys in each group with three girls in each group.
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