Answer:
Step-by-step explanation:
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Answer:
The recursive rule for account balance at the beginning of the nth month will be given by and
where, n = 1, 2, 3, .....
Step-by-step explanation:
On January 1, 2006, I have $100 in a savings account that earns interest at a rate of 1% per month. On the last day of every month, I deposit $75 in the account, beginning in January.
So, at the end of the month of January, the added amount to the account is $75 and 1% of $100 i.e. 1$.
Then, total $(75 + 1) = $76 is being added at the end of each month.
So, the recursive rule for account balance at the beginning of the nth month will be given by and
where, n = 1, 2, 3, ..... (Answer)
The simplified expression is
Explanation:
The given expression is
Let us simplify the expression.
Multiplying the numbers in the numerator, we have,
Dividing the term 144 by 3, which results in 48.
Thus, we have,
Applying the fraction rule , we get,
Applying the exponent rule , we have,
Thus, the simplified expression is