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2 years ago

5

Tom practiced piano 1 and 1/3 hours on Monday. If he spent half as much time practicing on Tuesday, how long did he practice on

Tuesday? Please show/tell me how you got the answer!!

1 answer:

PtichkaEL [24]2 years ago

3 0

Answer: 2/3 hours

Step-by-step explanation: 1 1/3 will equal 4/3 as you have a whole number equaling 3/1 so then you divide by two and get 2/3

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Square A has an area of 18a2 + 862 – 24ab.

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2 years ago

Tyler can shovel the driveway in 2 hours Dakota can complete the job in 90 minutes if they work together how long will it take

topjm [15]

One JOB = 1 and 2 hours = 120 min

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Dakota<span> Rate per minute: 1/90 (in 1 minute he performes 1/90 of the job)

Tyler's + Dakota's rate per 1 minute = 1/120 + 1/90 = 7/360 (Job/minutes)

7/360 of the job was performed in 1 minute
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2 years ago

Circumference (Level 2)

DENIUS [597]

Answer:

d=4.14

Step-by-step explanation:

use the equation d=2r

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4.13803≈4.14

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2 years ago

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Use spherical coordinates. evaluate xyz dv e , where e lies between the spheres ρ = 4 and ρ = 6 and above the cone ϕ = π/3.

sergey [27]

Set

$x=\rho\cos\theta\sin\varphi$

$y=\rho\sin\theta\sin\varphi$

$z=\rho\cos\varphi$

so that the volume element is

$\mathrm dV=\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi$

The integral is then

$\displaystyle\iiint_Exyz\,\mathrm dV=\int_{\varphi=0}^{\varphi=\pi/3}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=4}^{\rho=6}\rho^5\cos\theta\sin\theta\sin^3\varphi\cos\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\rho$

$=\displaystyle\left(\int_0^{\pi/3}\sin^3\varphi\cos\varphi\,\mathrm d\varphi\right)\underbrace{\left(\int_0^{2\pi}\cos\theta\sin\theta\,\mathrm d\theta\right)}_0\left(\int_4^6\rho^5\,\mathrm d\rho\right)$

and so evaluates to 0.

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2 years ago

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xenn [34]

1/72 is your answer. Hope this helps!

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2 years ago

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