Answer: Any real number x as long as
and 
In other words, anything but 0 or -2/3 is valid.
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Explanation:
Set the denominator equal to zero and solve for x
2(3x^2 + 2x) = 0
3x^2 + 2x = 0
x(3x + 2) = 0
x = 0 or 3x+2 = 0 .... zero product property
x = 0 or 3x = -2
x = 0 or x = -2/3
If either x = 0 or x = -2/3, then the denominator 2(3x^2 + 2x) will be zero. But recall that we cannot have zero in the denominator. Dividing by zero is not allowed. The expression is undefined when we divide by zero.
Therefore, we must exclude x = 0 and x = -2/3 from the domain. Any other real number is valid as an x input.
Answer: the domain is - infinity , + infinity
Step-by-step explanation:
A= 108 centimeters sqaured if you are on oddeseyware thats the correct answer
Answer:
6 and 10
Step-by-step explanation:
xy=60
2(x+y)=32
x+y=16
y=16-x
Substitute y into area equation
x(16-x)=60
16x-x^2=60
x^2-16x+60=0
(x-10)(x-6)=0
x=10, 6
y=6, 10