I'm gonna do this 2 ways because I'm not sure what you mean about the line. I'm going to indicate greater than or equal to with >=.
1st I'll solve for
r/15 >= -3
multiply by 15 on each side
r >= -45
Next I'll solve for
r/15 >= 3
multiply 15 on each side
r >= 45
So depending on if that is a 3 or -3 that is how you would do it....
So did I read the problem right?
Answer:
It is given that in triangle XYZ, XY = 13, YZ=20, and XZ=25.Using the law of cosines, we have
CosC=\frac{a^2+b^2-c^2}{2ab}
cosZ=\frac{(YZ)^2+(XZ)^2-(XY)^2}{2(YZ)(XZ)}
CosZ=\frac{(20)^2+(25)^2-(13)^2}{2(20)(25)}
CosZ=\frac{400+625-169}{1000}
CosZ=\frac{856}{1000}
CosZ=0.856
Z=cos^{-1}(0.856)
Z=37.13^{\circ}
Step-by-step explanation:
Answer:
2.5(x-1)+4.5(-x-2)
2.5x-2.5-4.5x-9
-2x-11.5
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
We need to determinate who doesn't use anything, so first we must know the real number of who are practising: a person can do more things.
For doing this, is better use a three-circles graphic, but we try to do without it.
So
- 16 pool + gym + track, and this number is sure
- 38 gym + pool, but this number includes the people of 1st point. We must know who do only gym + pool: 38 - 16 = 22
- 31 pool + track, this number also includes people of 1st point, so: only pool + track 31 - 16 = 15
- 33 gym + track, this number also includes people of 1st point, so: only gym + track 33 - 16 = 17
now:
- 67 gym, we must know who use only gym: 67 - 16 (gym + pool + track) - 22 (gym + pool) - 17 (gym + track) = 12
- 62 pool, we must know who use only pool: 62 - 16 (gym + pool + track) - 22 (gym + pool) - 15 (pool + track) = 9
- 56 track, we must know who use only track: 56 - 16 (gym + pool + track) - 15 (pool + track) - 17 (gym + track) = 8
now we must now who do some facility: let's sum all
16 + 22 + 15 + 17 + 12 + 9 + 8 = 99
99/100 practise something
So only 1/100 doesn't use nothing
The probability is 1%