4 factors that influence how drugs affect the body

What is one condition that must be met for a population to be in genetic equilibrium? A. There is nonrandom mating. B. There is

Ksenya-84 [330]

Answer:

C. There is no genetic drift

Explanation:

A population is said to be in genetic equilibrium when the genetic variation of a population remains constant over many generations.

For a population to remain in genetic equilibrium it is necessary that external factors that disturb the equilibrium should not be present.

The external factors that are responsible for disturbing the genetic equilibrium are mutations, non-random mating, genetic drift and gene flow.

Genetic drift occurs when due to a chance event the allele frequency of a population either increases or decreases and this is usually common in small populations.

Thus, genetic drift should not occur so that the population can be in genetic equilibrium.

3 0

3 years ago

Any three ways by which harmful subtances could contaiminate bod

saul85 [17]

Through a cut or an injury where any skin has been broken.

An infection through an animal's bite or sting.(Like the West Nile Virus which spreads though mosquito bite, or Rabies though an infected mammal's bite).

Can be inhaled or consumed and go from the lungs into the other organs causing harm internally.

4 0

2 years ago

. The value of Maggie's car decreased by 10% since last year, when she bought it. If the car is now worth $15,000.00, how much w

Phoenix [80]

You multiply 15,000 by .1, which equals 1,500. Then you add that to 15,000. This equals 16,500. That is your answer.

7 0

3 years ago

2. Dominant trait: cleft chin (C) Mother’s gametes: Cc

andre [41]

.2. Offspring Genotypes will be Cc or cc.

Offspring phenotypes : Cleft chin or no cleft chin.

% chance child will have cleft chin: 50%

3. % chance child will have arched feet: 25%

4. % chance child will have blonde hair: 50%

5. % chance child will have normal vision: 25%

Explanation:

CASE 1 :

Dominant trait: cleft chin (C)

Recessive trait: lacks cleft chin (c)

Father’s gametes: cc

Mother’s gametes: Cc

There are two possible combination of Gametes ,

C fom mother and c from father= Cc

c from mother and c from father = cc

Gametes of Cc Parents= $\frac{1}{2}C + \frac{1}{2} c$ ........(i)

Gametes of cc parents = $\frac{1}{2}c + \frac{1}{2}c$ .........(ii)

Combining (i) and (ii) we get,

$\frac{1}{2} Cc + \frac{1}{2} cc$

There fore offspring Genotypes will be Cc or cc

Offspring phenotypes :

Genotype Cc then phenotype= Cleft chin

Genotype cc then phenotype = Lacks cleft chin.

percentage chance child will have cleft chin = $\frac{0.5}{1}$ ×100

Therefore the chance is 50%.

CASE 2 :

Dominant trait: flat feet (A)

Recessive trait: arched feet (a)

Mother’s gametes: Heterozygous (Aa)

Father’s gametes: Heterozygous (Aa)

There are four possible combination of genotypes are =AA , Aa, Aa and aa

i.e. A from mother, A from father= AA

A from mother, a from father =Aa

a from mother, A from Father = Aa

a from mother, a from father = aa

Gametes of Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

Gametes of other Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

..................................................................................

$\frac{1}{4} AA + \frac{1}{4} Aa$

+ $\frac{1}{4} Aa$ + $\frac{1}{4} aa$

..........................................................................................

$\frac{1}{4}AA + \frac{1}{2}Aa +\frac{1}{4} aa$

Offspring Genotypes will be: AA or Aa or aa

Offsprings phenotype will be:

Genotype AA then phenotype will be Flat feet

Genotype Aa then phenotype will be flat feet

Genotype aa then Phenotype will be arched feet.

Percentage chance child will have arched feet = $\frac{0.25}{1}$ × 100 = 25%

CASE 3:

Dominant trait: Brown hair (B)

Recessive trait: Blonde hair (b)

Mother’s gametes: Homozygous recessive (bb)

Father’s gametes: Heterozygous (Bb)

This case is very similar to the case 1 as one parent is homozygous recessive and other parent is heterozygous.

Resulting in half Bb and halve bb combination.

Genotypes will be Bb or bb

Phenotypes will be :

Genotype Bb then phenotype Brown hair

Phenotype bb then Phenotype bb.

% chance child will have blonde hair: 50%

CASE 4:

Dominant trait: farsightedness (F)

Recessive trait: normal vision (f)

Mother’s gametes: Heterozygous (Ff)

Father’s gametes: Heterozygous (Ff)

This Case is similar to case 2

it will result in one-fourth FF , half Ff and one-fouth ff combination.

Therefore Genotypes will be: FF, Ff and ff

Phenotypes:

Genotype FF then phenotype farsightedness

Genotype Ff then phenotype farsightedness

Genotype ff then phenotype normal vision.

% chance child will have normal vision: 25%

3 0

3 years ago

Which material has the highest thermal conductivity? Which material has the highest electrical conductivity? Explain why thermal

olga55 [171]

Answer:Silver

Explanation:Silver has the highest electrical conductivity of all metals. In fact, silver defines conductivity - all other metals are compared against it. On a scale of 0 to 100, silver ranks 100, with copper at 97 and gold at 76.

4 0

3 years ago

Read 2 more answers