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3 years ago

Derivation of mean, mode, and median: ...?

1 answer:

5 0

The answer from the question above is the following.

The mean is the sum of observations divided by the number of observations.
The Mode is the observation that occurs frequently.
Lastly, the median is a value of middle observation if an uneven number of observations or the average of the two middle if the even number of observations.

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A population of 60 foxes in a wildfire preserve doubles in size every 12 years. The function y = 60*2^x, where x is the number o

alexira [117]

There will be 240 foxes

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3 years ago

"Immediately after a ban on using hand-held cell phones while driving was implemented, compliance with the law was measured. A r

sergiy2304 [10]

Answer:

(a) Null Hypothesis, $H_0$ : $p_1-p_2=0$ or $p_1= p_2$

Alternate Hypothesis, $H_A$ : $p_1-p_2\neq 0$ or $p_1\neq p_2$

(b) We conclude that there is a statistical difference in these two proportions measured initially and then one year later.

Step-by-step explanation:

We are given that a random sample of 1,250 drivers found that 98.9% were in compliance. A year after the implementation, compliance was again measured to see if compliance was the same (or not) as previously measured.

A different random sample of 1,100 drivers found 96.9% compliance."

Let $p_1$ = proportion of drivers that were in compliance initially

$p_2$ = proportion of drivers that were in compliance one year later

(a) Null Hypothesis, $H_0$ : $p_1-p_2=0$ or $p_1= p_2$ {means that there is not any statistical difference in these two proportions measured initially and then one year later}

Alternate Hypothesis, $H_A$ : $p_1-p_2\neq 0$ or $p_1\neq p_2$ {means that there is a statistical difference in these two proportions measured initially and then one year later}

The test statistics that will be used here is Two-sample z proportion statistics;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{ \frac{\hat p_1(1-\hat p_1)}{n_1} + \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of drivers in compliance initially = 98.9%

$\hat p_2$ = sample proportion of drivers in compliance one year later = 96.9%

$n_1$ = sample of drivers initially = 1,250

$n_2$ = sample of drivers one year later = 1,100

(b) So, the test statistics = $\frac{(0.989-0.969)-(0)}{\sqrt{ \frac{0.989(1-0.989)}{1,250} + \frac{0.969(1-0.969)}{1,100}} }$

= 3.33

Now, P-value of the test statistics is given by;

P-value = P(Z > 3.33) = 1 - P(Z $\leq$ 3.33)

= 1 - 0.99957 = 0.00043

Since in the question we are not given with the level of significance so we assume it to be 5%. Now at 5% significance level, the z table gives critical values between -1.96 and 1.96 for two-tailed test.

Since our test statistics does not lies within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that there is a statistical difference in these two proportions measured initially and then one year later.

7 0

3 years ago

Encontrar el valor d la variable

Yuki888 [10]

I think it may be 5+3 and carry the one up top to get the sum of 56.

7 0

3 years ago

There are 12 boys and 16 girls in a classroom. Which represents the simplified ratio of girls to students in the

Arturiano [62]

Answer:

I think it is 4 to 3

Step-by-step explanation:

if I am wrong I'm sorry

3 0

3 years ago

Read 2 more answers

Does this graph has a minimum or maximum y=4x^2+4

Lorico [155]

Answer:

It has a minimum and no maximum.

Step-by-step explanation:

This is the graph of a parabola that opens up, so it has a minimum but no maximum.

7 0

3 years ago