Ask question

Ask question

All categories

3 years ago

8

What is the square root of negative 100?

2 answers:

sattari [20]3 years ago

6 0

Answer:

0 + 10i

Step-by-step explanation:

Kamila [148]3 years ago

4 0

The square root of negative 100 can be dissected step by step. The square root of 100 is 10 however there is no such thing as square root of something negative, thus the imaginary notion is applied. square root of -1 is equal to i .Hence the answer to this problem is 10 i.

You might be interested in

Could someone please help

alexdok [17]

Answer:

Answer:<em>I think that is right...</em>

Answer:<em>I think that is right...Please make me brainliest...</em>

3 0

2 years ago

F. Use the information above to find 345 + 15. Explain your thinking.

8090 [49]

Answer:

360

Step-by-step explanation:

ikaw na ang mag step by step niyan paki barainlest

6 0

3 years ago

The power generated by an electrical circuit (in watts) as a function of its current ccc (in amperes) is modeled by: P(c)=-20(c-

alekssr [168]

Answer:

The current that produces maximum power is 3A

Step-by-step explanation:

Given

$P(c) = 20(c - 3)^2$

Required [Missing from the question]

The current that produces maximum power

First, we represent the function in standard form

$P(c) = 20(c - 3)^2$

$P(c) = 20(c - 3)(c - 3)$

Open bracket

$P(c) = 20(c^2 -6c+ 9)$

$P(c) = 20c^2 -120c+ 180$

The maximum value of c is:

$Max(c) = \frac{-b}{2a}$

Where:

$f(x) = ax^2 + b^2 + c$

By comparison: $P(c) = 20c^2 -120c+ 180$

$a = 20$

$b = -120$

$c = 180$

So, we have:

$Max(c) = \frac{-b}{2a}$

$Max(c) = \frac{-(-120)}{2 * 20}$

$Max(c) = \frac{120}{40}$

$Max(c) = 3$

5 0

3 years ago

Which type of graph would allow us to quickly see how many months between 100 and 200 students were treated?

Yuki888 [10]

The type of graph that would allow us to quickly see how many students were treated would be a Bar graph.

7 0

3 years ago

Read 2 more answers

Find the volume of the box

Rudik [331]

answer is B. detrjrajaetkterjaejq

6 0

2 years ago