Given:
The side of square = 12 in.
Scale factor of enlargement = 3 in : 2 m
To find:
The proportion that is use to solve the side length, x, of the enlarged square.
Solution:
Let, the side of length of enlarged square = x m
In case of enlargement the corresponding sides are proportional.



Divide both sides by 3.


Therefore, the required proportion is
and the side length of the square after enlargement is 8 m.
Answer:
p-q= -4
p=q-4
x^2 + px + q=0
=> x^2 + (q-4)x + q = 0
d= b^2-4ac
=(q-4)^2 - 4(1)(q)
= q^2 + 16 -8q - 4q
=q^2 -12q+16
given that D=16
q^2 -12q+16 = 16
=> q^2 -12q = 0
=> q^2 = 12q
=> q = 12q/q
=> q= 12
Therefore the value of q is 12 and the value of p is q-4 = 12-4= 8
Hope you understood............
Answer: 
Step-by-step explanation:

Divide by 23

Extract the square root.

The statement the graphs of both functions have a vertical asymptote of x=0 and statement unlike the graph of function f, the graph of function g decreases as x increases are true.
<h3>What is a function?</h3>
It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have two functions:
f(x) = lnx
g(x) = -5 lnx
The domain of the both functions x > 0
The function will be touch the y-axis when x reaches to the infinite.
The graphs of both functions have a vertical asymptote of x=0.
Unlike the graph of function f, the graph of function g decreases as x increases.
The graph of function g is the graph of function f vertically stretched by a factor of 5 and reflected over the x-axis.
Thus, the statement the graphs of both functions have a vertical asymptote of x=0 and statement unlike the graph of function f, the graph of function g decreases as x increases are true.
Learn more about the function here:
brainly.com/question/5245372
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It’s 5 and 4
Have fun on that test