I find it easier if you draw out people(not perfectly just make a circle or something) and then circle every 2 people to count for the men. There are 16 men in the gym.
Answer:
The standard deviation will remain unchanged.
Step-by-step explanation:
Given
Solving (a): The range
This is calculated as:
Where:
So:
Solving (b): The variance
First, we calculate the mean
The variance is calculated as:
So, we have:
![\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2]](https://tex.z-dn.net/?f=%5Csigma%5E2%20%3D%5Cfrac%7B1%7D%7B6-1%7D%2A%5B%28136%20-%20135%29%5E2%20%2B%28129%20-%20135%29%5E2%20%2B%28141%20-%20135%29%5E2%20%2B%28139%20-%20135%29%5E2%20%2B%28138%20-%20135%29%5E2%20%2B%28127%20-%20135%29%5E2%5D)
![\sigma^2 =\frac{1}{5}*[162]](https://tex.z-dn.net/?f=%5Csigma%5E2%20%3D%5Cfrac%7B1%7D%7B5%7D%2A%5B162%5D)
Solving (c): The standard deviation
This is calculated as:
--- approximately
Solving (d): With the stated condition, the standard deviation will remain unchanged.
Answer:
I think it 168 square units
Step-by-step explanation:
hope it helps
Answer:
A=63.6 approximately
Step-by-step explanation:
P=14.28
p=1/4(2pi*r)
p=1/2pi*r
14.28=1/2pi*r
28.56=3.14*r
r=9...... approximately
A=1/4pi*r^2
A=0.25*3.14*81
A=63.6......approximately
Answer:
x < 13
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define</u>
3x < 39
<u>Step 2: Solve for </u><em><u>x</u></em>
- Divide 3 on both sides: x < 13
Here we see that any value <em>x</em> smaller than 13 would work as solution to the inequality.
