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3 years ago

Shae makes $12.50 an hour. If she works 6.5 hours a day, after how many days will she have earned $500?

Mathematics

2 answers:

Wittaler [7]3 years ago

6 0

7 Days She Have earned over 500
6 days won't be enough since by then she still haven't reached 500

Vsevolod [243]3 years ago

3 0

She would make $81.25 after 6.5 hours a day by multiplying $12.50 by 6.5

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How many ways are there for six dogs and four cats to sit in a row in a strawberry field so that no two cats sit next to each ot

pickupchik [31]

Answer: 5,760

Step-by-step explanation:

$\\$ It was given that each dog is distinct from other dogs and each cat is distinct from other cats, Also from the hint given, the First position is for the dogs. $\\$ Let D represent the dogs and C represent the Cat , then we have

$\\$ D C D C D C D C D D or

$\\$ D D C D C D C D C D or

$\\$ D C DD C D C D C D or

$\\$ D C D C D D C D C D or

$\\$ D C D C D C DD C D

$\\$ Each of the arrangements above could be done in

$\\$ 2 x 4! x 4! ( it is constant that D is starting , so I am only left with the arrangement of the remaining 5 D's , out of the remaining 5 D's it is also constant that tow of them will be together and this could be done in 2 ways, so I have 4! left for the D's and 4! also for the C's )

$\\$ = 2 x 24 x 24

$\\$ = 1 , 152

$\\$ The total arrangement = 5 x 1 , 152

$\\$ = 5,7 60 ways

3 0

3 years ago

4. Lee wanted to buy his mother flowers for Mother's Day. He bought 8

enot [183]

Answer:

Each tulip costs $1.50

Step-by-step explanation:

First, write an equation using the numbers given. It should look like this:

2.25(8) + 5x = 25.50

Next, multiply 2.25 by 8 to get: 18 + 5x = 25.50. Then, subtract 18 from both sides:

18 + 5x = 25.50

-18 -18

5x = 7.50

Finally, divide both sides of the equation by 5 to get $1.50

So, each tulip costs $1.50. Hope this helped!

3 0

3 years ago

WILL MARK BRAINLY FOR WHO EVER GETS THIS RIGHT

Vedmedyk [2.9K]

Answer:

The first option and the third option

Step-by-step explanation:

Since the figure moved 4 places down and 4 places to the right.

5 0

3 years ago

Read 2 more answers

The edge length of a cube is changing at a rate of 10 in/sec. At what rate is the cube's volume changing when the edge length is

olya-2409 [2.1K]

Given:

The edge length of a cube is changing at a rate of 10 in/sec.

To find:

The rate by which cube's volume changing when the edge length is 3 inches.

Solution:

We have,

$\dfrac{da}{dt}=10\text{ in/sec}$

We know that, volume of cube is

$V=a^3$

Differentiate with respect to t.

$\dfrac{dV}{dt}=3a^2\dfrac{da}{dt}$

Substituting $\dfrac{da}{dt}=10$ and a=3, we get

$\dfrac{dV}{dt}_{a=3}=3(3)^2(10)$

$\dfrac{dV}{dt}_{a=3}=3(9)(10)$

$\dfrac{dV}{dt}_{a=3}=270$

Therefore, the volume increased by 270 cubic inches per sec.

7 0

3 years ago

The logarithm of a number to the base V2 is k. What is its logarithm to the base 2v2 ?

kakasveta [241]

Answer:

$log_{2\sqrt 2} X = \frac{1}{3}k$

Step-by-step explanation:

Given

Let the number be X

From the first statement, we have:

$log_{\sqrt 2} X = k$

Required

Find $log_{2\sqrt 2} X$

$log_{\sqrt 2} X = k$

using the following law of logarithm

$log_ab = n, b=a^n$

So:

$log_{\sqrt 2} X = k$

$X = \sqrt{2}^k$

Substitute: $X = \sqrt{2}^k$ in $log_{2\sqrt 2} X$

$log_{2\sqrt 2} X = log_{2\sqrt 2} ( \sqrt{2}^k)$

$log_{2\sqrt 2} X = klog_{2\sqrt 2} \sqrt{2}$

Apply the following law:

$log_ab = \frac{log\ b}{log\ a}$

$log_{2\sqrt 2} X = k\frac{log\ \sqrt 2}{log\ {2\sqrt 2}}$

Express the square roots as power

$log_{2\sqrt 2} X = k\frac{log\ 2^\frac{1}{2}}{log\ {2 * 2^\frac{1}{2}}}$

$log_{2\sqrt 2} X = k\frac{log\ 2^\frac{1}{2}}{log\ {2^\frac{3}{2}}}$

using the following law of logarithm

$log_ab = n, b=a^n$

$log_{2\sqrt 2} X = k\frac{\frac{1}{2}log\ 2}{\frac{3}{2}log\ 2}}$

$log_{2\sqrt 2} X = k\frac{\frac{1}{2}}{\frac{3}{2}}}$

Rewrite as:

$log_{2\sqrt 2} X = k * \frac{1}{2} \div\frac{3}{2}$

$log_{2\sqrt 2} X = k * \frac{1}{2} *\frac{2}{3}$

$log_{2\sqrt 2} X = k * \frac{1}{1} *\frac{1}{3}$

$log_{2\sqrt 2} X = \frac{1}{3}k$

4 0

2 years ago