We will use the FOIL method to solve this.
(7x-7)(x+1)
Multiply 7x by x. Then, multiply 7x by 1. Then, multiply -7 by x. Then, Multiply -7 by 1.
Now, we need to simplify by combining like terms.
If you look, -7x and 7x are gone. This is because they cancel each other out.
I hope this helped and maybe consider giving me brainliest :)
Answer:
F. 6s > 4s +8
Step-by-step explanation:
From a reference point at the beginning of the track, Ward's car will be located 4s+8 feet down the track after s seconds. That is, it starts 8 feet down the track, and increases its distance by 4 feet every second.
From the same reference point, Heskey's car will be located 6s feet down the track after s seconds. Its distance starts from zero and is increasing at the rate of 6 feet every second.
For Heskey's distance to exceed Ward's distance you want ...
6s > 4s +8 . . . . . . matches choice F
17/32. You can turn 5/16 into 10/32. 17/32>10/32
Answer:
77 nickels
106 dimes
Step-by-step explanation:
Let there be n nickes and d dimes
Since there are 183 coins, we can write:
n + d = 183
Also, the value of nickel is 0.05 and dime is 0.1, total value is 14.45, so we can write:
0.05n + 0.1d = 14.45
Solving 1st equation for n, we have:
n = 183 - d
Putting this into 2nd equation and solving for d:
There are 106 dimes
Since, n = 183 - d
n = 183 - 106
n = 77
There are 77 nickels
Answer:
a) The function is constantly increasing and is never decreasing
b) There is no local maximum or local minimum.
Step-by-step explanation:
To find the intervals of increasing and decreasing, we can start by finding the answers to part b, which is to find the local maximums and minimums. We do this by taking the derivatives of the equation.
f(x) = ln(x^4 + 27)
f'(x) = 1/(x^2 + 27)
Now we take the derivative and solve for zero to find the local max and mins.
f'(x) = 1/(x^2 + 27)
0 = 1/(x^2 + 27)
Since this function can never be equal to one, we know that there are no local maximums or minimums. This also lets us know that this function will constantly be increasing.
