This is how I would solve it:

1st # = x 4(x+1)=3x+18
2nd # = x+1 4x+4=3x+18
4x=3x+14
x=14

To check: 15x4=60; 60-42=18. <u>1st # = 14; 2nd # = 15.</u>

5 0

3 years ago

What is the volume of a hemisphere with a radius of 2.3m round to the nearest tenth of a cubic meter

kodGreya [7K]

Answer: $25.5 m^{3}$

Step-by-step explanation:

If the volume of a sphere is

$V=\frac{4}{3} \pi r^{3}$

Where $r=2.3 m$ is the radius

The volume of a hemisphere is half the volume of the total sphere:

$V_{hemisphere}=\frac{V}{2}=\frac{\frac{4}{3} \pi r^{3}}{2}$

$V_{hemisphere}=\frac{2}{3} \pi r^{3}$

Solving this equation:

$V_{hemisphere}=\frac{2}{3} \pi (2.3 m)^{3}$

Finally:

$V_{hemisphere}=25.48m^{3} \approx 25.5 m^{3}$

5 0

3 years ago

Complete the table by using your knowledge of the formula for simple interest.​

Complete the table by using your knowledge of the formula for simple interest.