2x+y+3=0
...................
Answer: The speed is 22.2 mi/hr and woman is 8° north relative to the surface of the water.
Step-by-step explanation:
Since we have given that
Speed at which woman walks due west = 3 mi/hr
Speed at which ship moving due north = 22 mi/hr
Now it forms "Pythagorus theorem":
So, it becomes,

And the direction of the woman relative to the surface of the water is given by

Hence, the speed is 22.2 mi/hr and woman is 8° north relative to the surface of the water.
F = 18 ft.
The law of cosines states
c² = a² + b² - 2ab cos C
Using our information, we have
c² = 23² + 16² - 2(23)(16)cos 52
c² = 529 + 256 - 736cos 52
c² = 785 - 736cos 52
c² = 331.8732
Taking the square root of both sides, we have
c = √331.8732 = 18.22 ≈ 18
-4× = 16 answer: -4
Step-by-step explanation:
-4 × -4 = 16