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3 years ago

A {1,2,3,4} B {2,4,9,16} C {1,2} D {1,2,3,4,9,16}

Mathematics

2 answers:

Greeley [361]3 years ago

8 0

The range is the {2,4,9,16}, B, because the range is the set of y-values.

The answer is B.

I hope this helps. :)

MaRussiya [10]3 years ago

7 0

Answer:

Step-by-step explanation:

The range of the function consists of the set of output values ( on the right).

So its {2 4 9 16}

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Lin father is paying for a 20 meal he has a 15 off coupon for the meal what is the total after the discount

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Answer:

Step-by-step explanation:

20÷100=0.2

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3 years ago

I don’t understand stand this question someone please help me with work shown

djyliett [7]

Answer:

60°

please look into the solution down here.

Step-by-step explanation:

since BD bisects it, then the angles should be bisected symmetrically, or in other words, ANGLE ABD = angle DBC,

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3 years ago

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Answer:

Step-by-step explanation:

The pattern is: add two more than you did before: starting from 2.

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3 years ago

An article presents voltage measurements for a sample of 66 industrial networks in Estonia. Assume the rated voltage for these n

kramer

Answer:

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 232 V

Sample mean, $\bar{x}$ = 231.5 V

Sample size, n = 66

Sample standard deviation, s = 2.19 V

Alpha, α = 0.05

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 232\\H_A: \mu \neq 232$

We use Two-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n-1}} }$ Putting all the values, we have

$t_{stat} = \displaystyle\frac{231.5- 232}{\frac{2.19}{\sqrt{66}} } = -1.8548$

Now,

$t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = \pm 1.9971$

Since,

$|t_{stat}| > |t_{critical}|$

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

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3 years ago