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3 years ago

A soda container holds 51\2 gallons of soda .how many

1 answer:

8 0

If the Soda holds 51/2 Of a gallon of Soda you need to 51 by 2 which is 25.5
2
2[51
-4
----

then add the 1
25
2[51
-4 2x5 equals 10
----
11
- 10
------
1 half of 2 is 1 half of 1 is 0.5 1 is your remainder 1 equals 0.5
25 + 0.5 equals 25.5 that's how many gallons you have. :)

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Solve the quadratic equation by completing the square. x^2 - 10x + 18 = 0

serious [3.7K]

Okay so basically, you subtract 18 on both sides since the 18 doesn't work, making the equation
x² - 10x = -18
So then you add (b/2)², which is 25, to both sides, to get
x² - 10x + 25 = 7
After this, you factor.
(x-5)(x-5) = 7
Then you simplify.
(x-5)² = 7
Then you solve for x.
√(x-5)² = √7
x-5 = (+ or -)√7

~ x= 5 (+ or -)√7 ~

Hope this helps!

3 0

3 years ago

A rectangle has vertices W(2,3), X(2,6), Y(7,6), and Z(7,3).

KiRa [710]

Answer:

Step-by-step explanation:

A rectangle has 4 sides.

2 of them are lengths and 3 of them are widths.

We can simply use coordinate geometry (without graphing) to find side lengths of the rectangle. We will use Distance Formula.

We can find all the 4 lengths by using Distance Formula from points:

W and X

X and Y

Y and Z

W and Z

Note, that we don't need to find all 4 of them individually, because 2 are lengths (same) and 2 are widths (same). Thus we can find

Distance of WX, which would be same as distance of YZ

also

Distance of XY which would be same as distance of WZ

Note: Distance Formula is $D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$ where D is the distance, x_1, y_1 is the first coordinate points and x_2,y_2 is the second coordinate points

4 0

3 years ago

Sketching a Hyperbola In Exercises 19-32, find the center, vertices, foci, and the equations of the asymptotes of the hyperbola.

zlopas [31]

Step-by-step explanation:

her this is the answer for the question

7 0

2 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

marusya05 [52]

Answer:

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

Step-by-step explanation:

We have the following info given:

$n= 955$ represent the sampel size slected

$x = 812$ number of students who read above the eighth grade level

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

The confidence interval for the proportion would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the significance is $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution and we got.