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Ronch [10]
3 years ago
9

A soda container holds 51\2 gallons of soda .how many

Mathematics
1 answer:
victus00 [196]3 years ago
8 0
If the Soda holds 51/2 Of a gallon of Soda you need to 51 by 2 which is 25.5
   2
2[51
  -4
  ----

then add the 1 
   25
2[51
  -4            2x5 equals 10
  ----
   11
-  10
  ------
       1        half of 2 is 1 half of 1 is 0.5  1 is your remainder 1 equals 0.5 
                 25 + 0.5 equals <span>25.5 that's how many gallons you have. :)</span> 

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Grace [21]
Tan(61)= x/16 --> 16 x tan(61) = 59.89 = 59.9
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3 years ago
Three identical coins, labeled A, B, and C in the figure, lie on three corners of a square 10.0 cm on a side. Determine the x co
shepuryov [24]
<span>The line of symmetry of the triangle bisects the right angle and the diagonal of the square.
The line is 1/2 the length of the square's diagonal :

(1/2)(10√2) = 5√2. 

</span>Let CG be a distance x from the vertex of the right angle in the triangle.
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(1)(x) = (2)(5√2 - x)</span>
x = 10√2 - 2x
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<span>x = (10/3)√2. 
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Using Pythagorean theorem,
x^2 + y^2 = c^2
 
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and x = y,
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</span>
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5 0
3 years ago
4. Dayon and Naqueal go on a run everyday after school. For every 2 blocks Naqueal
irakobra [83]

Answer:

A. 2:1

B. 10:5

Naquel runs twice as much as Dayon.

8 0
4 years ago
A man and a woman agree to meet at a cafe about noon. If the man arrives at a time uniformly distributed between 11:40 and 12:10
kompoz [17]

Answer:

0.3888

Step-by-step explanation:

To solve the exercise we need a neutral time, so we define at 12:00 as time 0.

If the man arrives in a uniformly distributed time between 11:40 and 12:10, the time is distributed from -20 to 10.

If the woman arrives in a time evenly distributed between 11:45 and 12:20, the time is distributed from -15 to 20.

Assuming that each one arrives at 12: X and 12: Y for men and women, then the space of our time is defined as

Man [-20,10]

Woman [-15,20]

So,

f_x(x)=\frac{1}{10-(-20)}=\frac{1}{30}\\f_y(y)=\frac{1}{20-(-15)}=\frac{1}{35}

Then,

f_{xy}(x,y)=f_x(x)f_y(y)=\frac{1}{30} \frac{1}{35} = \frac{1}{1050}

The probability of finding an arrival less than 5 minutes is

P(|X-Y|\leq 5) = \int\limit^20_{-15} \int\limit^{x+5}_{x-5} f(x,y)dydx

P(|X-Y|\leq 5)= \frac{1}{1050}\int\limit^{20}_{-15} y|^{x+5}_{x-5}dx

P(|X-Y|\leq 5)= \frac{35*10}{900}=0.3888

6 0
3 years ago
IF A CUBE HAS VOLUME OF 1,331 MM, WHAT IS THE AREA OF THE BASE OF IT IN SQUARE MILLIMETERS
monitta
1331= lwh or 1331= x^3

So take cube root of both sides and you will get 11.

Since the formula for area is length times width, the answer is 11x11 which equals 121.

So the square area of the base is 121mm^2



4 0
3 years ago
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