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Illusion [34]
3 years ago
14

The archway of the main entrance of a university is modeled by the quadratic equation y = -x2 + 6x. The university is hanging a

banner at the main entrance at an angle defined by the equation 4y = 21 − x. At what points should the banner be attached to the archway?
A(1, 5.5) and (5.25, 6.56)
B(1, 5) and (5.25, 3.94)
C(1.5, 4.87) and (3.5, 4.37)
D(1.5, 5.62) and (3.5, 6.12)
EThere is no real solution.
Mathematics
2 answers:
katrin [286]3 years ago
5 0

Basically look for the intersection points of these two functions by setting them equal to each other.

-x^2 + 6x = 21/4 - x/4

-x^2 + (25/4)x - 21/4 = 0

x = 1 and x = 21/4


Plug these points back to any of the two original equations, you will get

(1,5) and (21/4, 63/16)


denpristay [2]3 years ago
4 0

1.5 ........ 5.25..... 3.94

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Answer:

C. 18

Step-by-step explanation:

We can find the numbers of payments using following formula

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PVr / PMT = 1 - (1+r)^-n

Where

PV = present value = $1,100

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n = numbers of month = ?

Placing values in the formula

(1+r)^-n = 1 - PVr /PMT

1.016^-n = 1-1100 x 0.016/71.50

1.016^-n = 0.753846154

-n x log 1.016 = log 0.753846154

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n = 17.8

n = 18 payments

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4 years ago
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Answer:

Here, answer is given in form of 4 figure labelled with inequality

Step-by-step explanation:

Given inequality are

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For matching with givens graph:

Simplifying...

A). 2x>(-6)

Divide 2 on both sides

x>(-3)

B). 6+x\leq 3

Add (-6) on both side.

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x

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Here, Answer is given in form of 4 figure labelled with inequality

4 0
3 years ago
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