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Arturiano [62]
3 years ago
6

How do you Graph 0.5x+0.8y=240

Mathematics
1 answer:
Schach [20]3 years ago
3 0

Answer:

y= 300 - 5/9x

Step-by-step explanation:

0.8y = 240 - 0.5x

divide both sides by 0.8,

y= 300 - 5/9x

-5/9 is your gradient

300 is your y-intercept

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Can someone please help me with this math question
inn [45]

Answer:

1. reflection across x-axis

2. translation 6 units to the right and 3 units up (x+6,y+3)

Step-by-step explanation:

The trapezoid ABCD has it vertices at points A(-5,2), B(-3,4), C(-2,4) and D(-1,2).

First transformation is the reflection across the x-axis with the rule

(x,y)→(x,-y)

so,

  • A(-5,2)→A'(-5,-2)
  • B(-3,4)→B'(-3,-4)
  • C(-2,4)→C'(-2,-4)
  • D(-1,2)→D'(-1,-2)

Second transformation is translation 6 units to the right and 3 units up with the rule

(x,y)→(x+6,y+3)

so,

  • A'(-5,-2)→E(1,1)
  • B'(-3,-4)→H(3,-1)
  • C'(-2,-4)→G(4,-1)
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Find the coordinates of point X that lies along the directed line segment from Y(-8, 8) to T(-15, -13) and partitions the segmen
Nataly_w [17]

Answer:

C. (-13, -7)

Step-by-step explanation:

The location of a point O(x, y) that divides a line AB with location A(x_1,y_1) and B(x_2,y_2) in the ratio m:n is given by:

x=\frac{m}{m+n} (x_2-x_1)+x_1\\\\y=\frac{m}{m+n} (y_2-y_1)+y_1

Therefore the coordinates of point X That divides line segment from Y(-8, 8) to T(-15, -13) in the ratio 5:2 is:

x=\frac{5}{5+2} (-15-(-8))+(-8)\\\\x=\frac{5}{7} (-15+8)-8=\frac{5}{7}(-7)-8=-5-8=-13 \\\\\\y=\frac{5}{5+2} (-13-8)+8\\\\y=\frac{5}{7} (-21)+8=5(-3)+8=-15+8=-7

Therefore the coordinates of point X is at (-13, -7)

6 0
3 years ago
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