All categories

3 years ago

The length of a classroom is 34 feet. What is the measurement in yards and feet?

1 answer:

8 0

The first thing you would do is divide 34 by 3, which is how many feet are in a yard, After you get your quotient, you will have a remainder, which will be your feet! Let me know if you have any questions!

You might be interested in

For every 4 basketballs there are 5 baseballs what is the ratio

77julia77 [94]

The answer would be 4:5 because they said basketballs first

7 0

3 years ago

HELP PLZZ ASAP !! a. The value of x is 6 , what is the value of y?

erastovalidia [21]

Answer:

a). y = 4.5

b) Scale factor = $\frac{3}{4}$

Step-by-step explanation:

a). Since, polygon Q is the scaled copy of polygon P

Both the figures will be similar.

Therefore, their corresponding sides will be proportional.

$\frac{x}{y} =\frac{4}{3}$

If x = 6,

$\frac{6}{y} =\frac{4}{3}$

y = $\frac{3\times 6}{4}$

y = 4.5

b). Since, polygon Q is the scaled copy of polygon P,

Polygon Q will be the image of preimage polygon P.

Scale factor = $\frac{\text{Length of a side of the image}}{\text{Length of a side of the preimage}}$

= $\frac{3}{4}$

6 0

3 years ago

Can anyone help me with this, I’ll give out brainliest. NO LINKS.

Sliva [168]

Answer:

89.132 inch

Step-by-step explanation:

“this shape is made up of one half-circle attached to a square with side lengths 16 inches. You can use 3.14 as an approximation.”

so, the square has a perimeter of 16 inch, four sides that will be 64 inch

then the half circle rule of perimeter of half circle: πr + 2r

=> perimeter of semicircle = π * 8 +2 * 8 = 41.132 inch

<em>without the bottom line of half circle= 41.132 -16 = 25.133 inch</em>

<em />

So total 25.133 + 64 =89.132 inch

have a great day and nc question

4 0

2 years ago

A complex fraction is equal to a number less than 1 if the denominator is greater than.....

bixtya [17]

If the denominator is greater than nominator.

3 0

3 years ago

Construct a 99% confidthence interval for the population mean .Assume the population has a normal distribution. A group of 19 ra

Kobotan [32]

<h2>Answer with explanation:</h2>

Confidence interval for mean, when population standard deviation is unknown:

$\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}}$

, where $\overline{x}$ = sample mean

n= sample size

s= sample standard deviation

$t_{\alpha/2}$ = Critical t-value for n-1 degrees of freedom

We assume the population has a normal distribution.

Given, n= 19 , s= 3.8 , $\overline{x}=22.4$

$\alpha=1-0.99=0.01$

A) Critical t value for $\alpha/2=0.005$ and degree of 18 freedom

$t_{\alpha/2}$ = 2.8784

B) Required confidence interval:

$22.4\pm ( 2.8744)\dfrac{3.8}{\sqrt{19}}\\\\=22.4\pm2.5058\\\\=(22.4-2.5058,\ 22.4+2.5058)=(19.8942,\ 24.9058)\approx(19.9,\ 24.9)$

Lower bound = 19.9 years

Uppen bound = 24.9 years

C) Interpretation: We are 99% confident that the true population mean of lies in (19.9, 24.9) .

5 0

3 years ago