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3 years ago

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Apple juice and cranberry juice have been mixed in the ratio 4:5. If the price of apple juice is 45 cents per pint and the price

of cranberry juice is $.08 per pint, what should the price of one pint of the mixture be?
PLZ ANSWER

1 answer:

Lunna [17]3 years ago

5 0

Answer:

0.24

Step-by-step explanation:

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Plz help its due TOMMOROW

sashaice [31]

Answer:

86%

Step-by-step explanation:

Let g represent the mean mark for the 10 girls in the class. Then the mean mark for the class was ...

10g +20(62%) = 30(70%)

g = 3(.7) -2(.62) . . . . . . . . . divide by 10 and subtract 2(.62)

g = .86 = 86%

The mean mark for girls was 86%.

_____

You can do this in your head if you consider it in terms of deviations from the mean. The second equation above can be rewritten and factored as ...

g = 70% +2(70% -62%)

That is, because there are 2 boys for every girl, the girl's score is above the mean by an amount that is 2 times the amount that the boy's score is below the mean. The boys' score is below by 8%, so the girls' score is above by 16%, so is 86%.

4 0

3 years ago

Anyone know how to find the area with the missing hypotenuse? Thank you!!!

suter [353]

Answer:

$15 {cm}^{2}$

Step-by-step explanation:

There's no need of hypotenuse for finding area of the triangle. To find the area of a triangle ,

Formula is = $\frac{1}{2} \times base \times height$

Base of the triangle = 10 cm

Height of the traingle = 3 cm

Area of the triangle = $\frac{1}{2} \times 10 \times 3 = 15 {cm}^{2}$

5 0

3 years ago

All squares are polygons.

ANEK [815]

True
True
False
False
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4 0

3 years ago

Read 2 more answers

Given the following three points, find by the hand the quadratic function they represent (0,6, (2,16, (3,33)

Lisa [10]

Answer:

$f(x) = 4x^2 - 3x + 6$

Step-by-step explanation:

Quadratic function is given as $f(x) = ax^2 + bx + c$

Let's find a, b and c:

Substituting (0, 6):

$6 = a(0)^2 + b(0) + c$

$6 = 0 + 0 + c$

$c = 6$

Now that we know the value of c, let's derive 2 system of equations we would use to solve for a and b simultaneously as follows.

Substituting (2, 16), and c = 6

$f(x) = ax^2 + bx + c$

$16 = a(2)^2 + b(2) + 6$

$16 = 4a + 2b + 6$

$16 - 6 = 4a + 2b + 6 - 6$

$10 = 4a + 2b$

$10 = 2(2a + b)$

$\frac{10}{2} = \frac{2(2a + b)}{2}$

$5 = 2a + b$

$2a + b = 5$ => (Equation 1)

Substituting (3, 33), and c = 6

$f(x) = ax^2 + bx + x$

$33 = a(3)^2 + b(3) + 6$

$33 = 9a + 3b + 6$

$33 - 6 = 9a + 3b + 6 - 6$

$27 = 9a + 3b$

$27 = 3(3a + b)$

$\frac{27}{3} = \frac{3(3a + b)}{3}$

$9 = 3a + b$

$3a + b = 9$ => (Equation 2)

Subtract equation 1 from equation 2 to solve simultaneously for a and b.

$3a + b = 9$

$2a + b = 5$

$a = 4$

Replace a with 4 in equation 2.

$2a + b = 5$

$2(4) + b = 5$

$8 + b = 5$

$8 + b - 8 = 5 - 8$

$b = -3$

The quadratic function that represents the given 3 points would be as follows:

$f(x) = ax^2 + bx + c$

$f(x) = (4)x^2 + (-3)x + 6$

$f(x) = 4x^2 - 3x + 6$

6 0

3 years ago

I don’t know how to do these problems so please help me.

Olin [163]

Answer:

36s^3

Step-by-step explanation:

3 0

3 years ago