Answer:
-p+78x+39
Step-by-step explanation:
Answer:
1) 39.5 ft^2
1) 139.15m^2
Step-by-step explanation:
2) area of a rectangle formula : LW
Area of a triangle:(bh)/2
Area of a semi circle:( Pi*r^2)/2
Area of a square: S^2
Area of figure one:
Lw+(b1*h1)/2+(b2*h2)/2
8*4+(2*3)/2+(3*3)/2
32+3+4.5=39.5
Area of fig 2:
S^2+(pi*r^2)/2
10^2+(3.14*5^2)/2
100+78.5/2
100+39.25=139.25
Answer:
A. If we consider two right triangles one Δ ABD and Δ BCE, where D(2,100) and E(1,60) points
B. From the graph, it is clear that the initial value of the graph is 60 m and it represents the initial position of the shark i.e. at t = 0 min, the shark was at a depth of 60 m from the water surface.
The slope of the graph is 40 means the rate of change of distance from the Ocean surface of the shark with respect to time in minutes will be 40 m per min.
Step-by-step explanation:
<u>Answer:</u>
The correct answer option is A. Loss of 9 oz.
<u>Step-by-step explanation:</u>
We are given that a cat's weight change -8 oz. while she was sick. It means that the cat lost 8 ounces of weight.
We are to determine whether which of the given answer options show a greater change in weight.
The correct answer for this is: loss of 9 oz which is a greater loss than 8 oz.
Answer: Line AC = 24 units and line BC = 12 units.
Step-by-step explanation: Please refer to the diagram attached for more details.
The right angled triangle ABC has been drawn with angle A measuring 30 degrees and line AB measuring 12√3. To calculate the other two unknown sides AC labelled b, and BC labelled a, we shall use the trigonometric ratios. However, in this scenario, we shall apply the special values of each trigonometric ratio. These are shown in the box on the top right in the picture. The proof is given in the second right angled triangle at the bottom part of the attached picture.
Assume an equilateral triangle with lengths 2 units on all sides and 60 degrees at all angles. Drawing a line perpendicular to the bottom line would divide the top angle into two equal halves (30 degrees each), and the bottom line also would be divided into two equal halves (1 unit each). So the hypotenuse will measure 2 units and the line at the base would measure 1 unit. By using the Pythagoras' theorem, we derive the third side to be √3 <u>(that is x² = 2² - 1², and then x² = 4 - 1, and then x² = 3 and finally x = √3).</u>
Therefore, in triangle ABC, using angle 30 as the reference angle, to calculate side AC;
Cos 30 = Adjacent/Hypotenuse
Cos 30 = (12√3)/b
b = (12√3)/Cos 30
Where Cos 30 is √3/2
b = (12√3)/√3/2
b = (12√3) * 2/√3
b = 12 * 2
b = 24
To calculate side BC;
Tan 30 = Opposite/Adjacent
Tan 30 = a/(12√3)
Tan 30 * 12√3 = a
Where Tan 30 = 1/√3
(1/√3) * 12√3 = a
12 = a
Therefore, the missing lengths in the right triangle are
AC = 24 units and BC = 12 units