Answer:

Step-by-step explanation:
We need to solve the quadratic equation
6 = x^2 -10x
Rearranging we get,
x^2-10x-6=0
Using quadratic formula to solve the quadratic equation

a= 1, b =-10 and c=6
Putting values in the quadratic formula

So, 
Answer: It helps because you already know it off the top of your head and you are able to break up a multiplication problem step by step in your head.
Step-by-step explanation:
First, we must find common denominators in order to subtract the terms. we can multiply 8/9 by 2/2 and 1/2 by 9/9.
we get:
16/18-9/18
16-9= 7 and we keep the same denominators, so our final simplified answer is:
7/18
hope this helped!! xx
Answer:
j = 15
Step-by-step explanation:

Answer:
-12
Step-by-step explanation:
The coordinates of B' are just 3 times the coordinates of B, so the multiplier in the dilation is 3.
C' is the point with coordinates 3 times the coordinates of C, making C'(3, -12).
The y-coordinate is -12.