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3 years ago

What is the median of 32, 28, 20, 33, and 22

Mathematics

2 answers:

Svetlanka [38]3 years ago

6 0

Answer:28

Step-by-step explanation:

Re-arrange either ascending or descending order

20,22,28,32,33

The middle one is 28

Let's Re-arrange in descending

33,32,28,22,20

Same thing as the first step 28

PtichkaEL [24]3 years ago

3 0

$\huge\boxed{28}$

The median is the middle number when the numbers are arranged in order.

Order the numbers from least to greatest. $20, 22, 28, 32, 33$

Find the number that is in the middle. $\boxed{28}$

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The ratio of dogs to cats at an animal shelter is 33 to 22. How many dogs are at the shelter if there is a total of 3030 animals

Elena-2011 [213]

D : c = 33 : 22
where d is the number of dogs and c is the number of cats;
and: d + c = 3030
33 c = 22 d / : 11
3 c = 2 d
From the other equation: c = 3030 - d
3 * ( 3030 - d ) = 2 d
9090 - 3 d = 2 d
5 d = 9090
d = 9090 : 5
d = 1818
Answer: There are 1818 dogs in the shelter.

4 0

3 years ago

34. Which is the rule for the linear<br> function graphed below?

Ivahew [28]

Answer:

We can note that this part of the graph is a linear function. This means that is has a general form: y = mx + c where m is the slop and c is the y-intercept (value of y at x=0). For the slope, we will use the points (0,2) and (3,5) to calculate it as follows: m = (y2-y1)/(x2-x1) = (5-2)/(3-0) = 1 For the y-intercept, we can note that at x=0, the value of y is 2. This means that the equation of the first part of the graph is: y = x + 2

Read more at Answer.Ya.Guru – https://answer.ya.guru/questions/703068-which-rules-define-the-function-graphed-below.html

8 0

3 years ago

Which of the following numbers is divisible by 3, 5, and 10?

Alex787 [66]

Answer:

D. 30

Step-by-step explanation:

A. 15

3 and 5 are liable. 10 is not

B. 20

5 and 10 liable. 3 is not.

C. 25

5 is liable. 3 and 10 is not.

D. 30

3, 5, and 10 are liable

8 0

3 years ago

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What is the formula of a circle in terms of its circumference <br> A=pi*r^2<br> C=2*pi*r

Alja [10]

"Formula of a circle" is too vague to be meaningful. Perhaps you meant, "Formula for the area of a circle in terms of its circumference."

The area of a circle in terms of its radius is A = πr^2. To put this formula to use, we have to know the radius of the circle. The circumference of a circle in terms of its radius is C = 2πr, so a formula for the radius is r = C / (2π).

Now let's find a formula for the area of a circle in terms of its circumference:

C C^2

A = πr^2 = π { ---------------- }^2 = ------------

2π 4π

or:

A = (C^2) / 4π

5 0

3 years ago

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You have D dollars to buy fence to enclose a rectangular plot of land (see figure at right). The fence for the top and bottom co

alex41 [277]

The perimeter of the rectangular plot of land is given by the expression below

$P=2x+2y$

On the other hand, since the available money to buy fence is D dollars,

$\begin{gathered} D=4(2x)+3(2y) \\ \Rightarrow D=8x+6y \\ D\rightarrow\text{ constant} \end{gathered}$

Furthermore, the area of the enclosed land is given by

$A=xy$

Solving the second equation for x,

$\begin{gathered} D=8x+6y \\ \Rightarrow x=\frac{D-6y}{8} \end{gathered}$

Substituting into the equation for the area,

$\begin{gathered} A=(\frac{D-6y}{8})y \\ \Rightarrow A=\frac{D}{8}y-\frac{3}{4}y^2 \end{gathered}$

To find the maximum possible area, solve A'(y)=0, as shown below

$\begin{gathered} A^{\prime}(y)=0 \\ \Rightarrow\frac{D}{8}-\frac{3}{2}y=0 \\ \Rightarrow\frac{3}{2}y=\frac{D}{8} \\ \Rightarrow y=\frac{D}{12} \end{gathered}$

Therefore, the corresponding value of x is

$\begin{gathered} y=\frac{D}{12} \\ \Rightarrow x=\frac{D-6(\frac{D}{12})}{8}=\frac{D-\frac{D}{2}}{8}=\frac{D}{16} \end{gathered}$ <h2>Thus, the dimensions of the fence that maximize the area are x=D/16 and y=D/12.</h2><h2>As for the used money,</h2> $\begin{gathered} top,bottom:\frac{8D}{16}=\frac{D}{2} \\ Sides:\frac{6D}{12}=\frac{D}{2} \end{gathered}$ <h2>Half the money was used for the top and the bottom, while the other half was used for the sides.</h2>

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1 year ago