The x -intercepts occur when f(x) =0
So,
(x-4)^2 = x^2 -8x + 16 -3 =0
x^2 -8x + 13 =0
Solving by the quadratic formula
x1 = 5.7321
x2 = 2.2679
(f+g)(x)=0
f (x) + g (x)=0
now,
substitute their values
x^2 -4x + x -18 = 0
x^2 -3x -18 =0
x^2 - 6x + 3x - 18 =0
x (x-6) + 3 (x-6) = 0
(x-6)(x+3) = 0
we have to find it's zeroes (or roots) now:
x-6 =0
x = 6
x +3 =0
x = -3
Answer:
71100139<u>2</u>
321000<u>7</u>59
Step-by-step explanation:
hope it helps ^o^
The answer to your question is D) √5x/5x.
I hoped this helped!
Answer:
1200 students at the school
Step-by-step explanation:
Let x be the total number of students at the school
50% ride the bus
600 students ride the bus
x*50% = 600
Changing to decimal form
.50x = 600
Divide each side by .5
.50x/.5 = 600/.5
x =1200
1200 students at the school
