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Ivan
4 years ago
14

Find dyldx. 3. y=2x sin(3x)

Mathematics
1 answer:
vredina [299]4 years ago
6 0

Answer:

\large\boxed{\dfrac{dy}{dx}=2\sin(3x)+6\cos(3x)}

Step-by-step explanation:

\dfrac{dy}{dx}=(2x\sin(3x))'\\\\\text{use}\ \bigg(g(x)\cdot f(x)\bigg)'=g'(c)f(x)+g(x)f'(x)\\\\\text{and}\ \bigg(f(g(x))\bigg)'=f'(g(x))\cdot g'(x)\\\\\dfrac{dy}{dx}=(2x)'(\sin(3x))+(2x)(\sin(3x))'\\\\\dfrac{dy}{dx}=2\sin(3x)+(2x)(\cos(3x)\cdot(3x)')\\\\\dfrac{dy}{dx}=2\sin(3x)+2x\cos(3x)\cdot3\\\\\dfrac{dy}{dx}=2\sin(3x)+6\cos(3x)

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