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IRINA_888 [86]
3 years ago
8

The domain of discourse is sets. Suppose some predicate Q is true for all elemenst of A: ∀a ∈ A Q(a). Recall the definition of s

ubset: X ⊆ Y is defined as ∀b ∈ X b ∈ Y . Suppose B ⊆ A and C ⊆ B. Prove that ∀c ∈ C Q(c)
Mathematics
1 answer:
Sloan [31]3 years ago
5 0

Answer:

See the step-by-step explanation

Step-by-step explanation:

Let c be any element of C. (I'm not sure wether you have to assume that C is non-empt or not)

C is a subset of B. That means that as c is  in C, it is also in B. (c \in C \Rightarrow  c \in B)

Now, B is a subset of A. It follows that as c \in B \Rightarrow c \in A.

That means c is an element of A. The predicate Q is true for all elements of A, including c.

Because we let c be any element of C, we have proven that the predicate Q is true for all elements in C.

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consider the line y= 2/3x-0. Find the equation of the line that is parallel to this line and passes through the point (8, 4).
tresset_1 [31]
Point-slope form of a line: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)

slope intercept form :
y=m+b

m=slope

If the line is parallel to y=2/3 x-0, the line will have the same slope, therefore the slope will be: 2/3.

Data:
(8,4)
m=2/3

y-y₀=m(x-x₀)
y-4=2/3(x-8)
y-4=2/3 x-16/3
y=2/3 x-16/3+4
y=2/3 x-4/3  (slope intercept form)

Answer: The equation of the line would be: y=2/3 x-4/3.


if we have the next slope "m",then the perendicular slope will be:
m´=-1/m

We have this equation: y=2/3 x+0; the slope is: m=2/3.

The perpendicular slope will be: m`=-1/(2/3)=-3/2

And the equation of the perpendicular line to : y=2/3 x+0, given the point (8,4) will be:

y-y₀=m(x-x₀)
y-4=-3/2 (x-8)
y-4=-3/2 x+12
y=-3/2x + 12+4
y=-3/2x+16

answer: the perpendicular line to y=2/3 x+0 , given the point (8,4) will be:
y=-3/2 x+16
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3 years ago
2x - y = 5
goldfiish [28.3K]
Im pretty sure that the answer it is A. 7
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Answer:

Step-by-step explanation:

17.5% of 360 = 17.5% * 360

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Step-by-step explanation:

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