Step-by-step explanation:
wheres the decimal to compare it to
Answer:
(2 x +1) ( x + 1) = 2 x² + 3 x + 1
Step-by-step explanation:
The steops used to find the product of (2 x + 1) (x + 1) are
=( 2 x )× x + (2 x) × 1 + x + 1
= 2 x² + 2 x + x + 1
= 2 x² + 3 x + 1
im not sure but maybe look up how to calculate volume of a cone.. then go from there :D
Answer:
Exact dimensions:



Approximate dimensions:



Step-by-step explanation:
Let's assume width of rectangle is w ft
The length of a rectangular flower bed is 2ft longer than the width
so,
length =w+2

now, we can find area

now, we can plug it


we are given area =6
so, we can set it equal
and then we can solve for w


we can use quadratic formula


now, we can compare and find a,b and c
a=1 , b=2 , c=-6


we know that dimension can never be negative
so, we will only consider positive value
Exact dimensions:



Approximate dimensions:


