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slamgirl [31]
2 years ago
14

 Can someone pleaseeee help if you’re correct I’ll give u brainlist

Mathematics
1 answer:
marusya05 [52]2 years ago
6 0

Answer:

JL = 8 m

KD = 8 m

Step-by-step explanation:

By 45° - 45° - 90° triangle theorem:

JK  =  \frac{1}{ \sqrt{2} } JD \\  \\JK  =  \frac{1}{ \sqrt{2} }  \times 8 \sqrt{2}  \\  \\  \red{JK  =   \boxed{8 }}\: m \\  \\ KD=  \frac{1}{ \sqrt{2} } JD \\  \\KD  =  \frac{1}{ \sqrt{2} }  \times 8 \sqrt{2}  \\  \\ \purple{ KD  =   \boxed{8 } }\:m\\  \\

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A notebook costs $4.50 plus sales tax . After sales tax , the notebook is $4.86. What is the sales tax rate?
UkoKoshka [18]

Answer:

8%

Step-by-step explanation:

0.36/4.50=0.08=8%

6 0
2 years ago
Read 2 more answers
WILL GIVE BRAINLIEST!<br> Translate into a variable expression. the sum of sixteen and c
Art [367]

Answer:

16+c

Step-by-step explanation:

Sum means we will have to add. When it says "sum of sixteen and c" it is telling us to add both sixteen and c together.

4 0
3 years ago
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The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?
omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

T_5 = 160

T_7 = 40

Required

T_6

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

\frac{T_7}{T_5} = \frac{40}{160}

Divide the numerator and the denominator of the fraction by 40

\frac{T_7}{T_5} = \frac{1}{4} ----- equation 1

Recall that the formula of a GP is

T_n = a r^{n-1}

Where n is the nth term

So,

T_7 = a r^{6}

T_5 = a r^{4}

Substitute the above expression in equation 1

\frac{T_7}{T_5} = \frac{1}{4}  becomes

\frac{ar^6}{ar^4} = \frac{1}{4}

r^2 = \frac{1}{4}

Square root both sides

r = \sqrt{\frac{1}{4}}

r = ±\frac{1}{2}

Next, is to solve for the first term;

Using T_5 = a r^{4}

By substituting 160 for T5 and ±\frac{1}{2} for r;

We get

160 = a \frac{1}{2}^{4}

160 = a \frac{1}{16}

Multiply through by 16

16 * 160 = a \frac{1}{16} * 16

16 * 160 = a

2560 = a

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

T_n = a r^{n-1}

Here, n = 6;

T_6 = a r^{6-1}

T_6 = a r^5

T_6 = 2560 r^5

r = ±\frac{1}{2}

So,

T_6 = 2560( \frac{1}{2}^5) or T_6 = 2560( \frac{-1}{2}^5)

T_6 = 2560( \frac{1}{32}) or T_6 = 2560( \frac{-1}{32})

T_6 = 80 or T_6 = -80

T_6 =±80

Hence, the 6th term is positive/negative 80

8 0
3 years ago
FIND THE MEASURE OF EACH MISSING ANGLE HURRY DUE AT 10
max2010maxim [7]
Because of a linear pair then because of vertical angles and because all angles have to be 180 added up

5 0
3 years ago
What is (-94)÷5+22÷22's square?
Paha777 [63]

Answer:

Error

Step-by-step explanation:

(-94)/5+22/22    Given

-18.8+1                PEMDAS (do -94/5 and 22/2)

-17.8                    Add the numbers

After you add the numbers, you take the square root. you will get the answer "Error" because you cannot take the square root of a negative number

5 0
3 years ago
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