Question

The equation of a linear function in point-slope form is y – y1 = m(x – x1). Harold correctly wrote the equation y = 3(x – 7) using a point and the slope. Which point did Harold use?

Answer 1

Harold used
x1 = 7
and y1 = 0
the points are (7,0)

Answer 2

Answer: equation of a linear function in point-slope form

Step-by-step explanation:

Given : The equation of a linear function in point-slope form passing through point $(x_1,y_1)$ is

$y -y_1 = m(x -x_1)$

The equation written by Harold correctly

$y = 3(x - 7)$

It can be written as:$y-0 = 3(x - 7)$

When we compare to the equation of a linear function in point-slope form, we get $y_1=0,\ x_1=7$

Hence, the point used by Harold = $(x_1,y_1)=(7,0)$