Answer:
A polynomial function that meet the conditions is x³ - 8x² + 5x + 14 = 0
Step-by-step explanation:
Hi there!
Let´s start writting a generic factored function. In this case, the function has 3 zeros so that the factored form will have 3 terms:
(x + a)(x + b)(x + c) = 0
For this expression to be 0, either (x+a) = 0 or (x+b) = 0 or (x+c) = 0
Then:
x + a = 0 ⇒ x = -a
x + b = 0 ⇒ x = -b
x + c = 0 ⇒ x = -c
Then, the values "a", "b" and "c" are equal to the zeros of the function but with opposite sign. Then, in our case:
a = 1
b = -2
c = -7
Then, the polynomial fuction will be:
(x + 1)(x - 2)(x - 7) = 0
Apply distributive property:
(x² - 2x + x -2)(x -7) = 0
(x² - x - 2)(x - 7)
x³ - x² - 2x - 7x² + 7x + 14 = 0
x³ - 8x² + 5x + 14 = 0
Then, a polynomial function that meets the conditions is:
x³ - 8x² + 5x + 14 = 0
Have a nice day!
With what? need to write at least 20 characters.
U have multply or divide there 2 number but y u dont do your homework tomorrow
Answer:
The maximum height of coin Jake tosses is 15 feet.
Step-by-step explanation:
Given Jake tosses a coin up in the air
and the height of coin is model by h(t)=
To find height of the coin when Jake tosses it:
When a coin is in the hand of Jake, time t=0
Height of coin is h(t)=
h(0)=
h(0)=6 feet.
Therefore, Height of coin at time t=0 is 6.
For maximum height of the coin,
h(t)=
Differentiating both side,
![\frac{d}{dt}h(t)=\frac{d}{dt}[(-16)t^{2} +24t+6]](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7Dh%28t%29%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B%28-16%29t%5E%7B2%7D%20%2B24t%2B6%5D)
![\frac{d}{dt}h(t)=\frac{d}{dt}[(-32)t+24]](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7Dh%28t%29%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B%28-32%29t%2B24%5D)
![\frac{d}{dt}[(-32)t+24]=0](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%5B%28-32%29t%2B24%5D%3D0)
t=
t=
t=0.75
Now,
h(t)=
h(0.75)=
h(0.75)=15 feet.
The maximum height of coin jake tosses is 15 feet.
