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Soloha48 [4]
4 years ago
14

A triangular prism has base that is a right triangle.

Mathematics
1 answer:
Schach [20]4 years ago
3 0
The dimensions can vary. Here is a picture of a triangular prism with a right-triangle base.

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Calculate the difference and enter it below. -9-(-10) Answer here​
WINSTONCH [101]

Answer:

-9-(-10)

=-9+10

=1

8 0
3 years ago
Read 2 more answers
{(-5,4),(3,-2),(3,4),(4,3)}<br><br> what is the domain and the range
dedylja [7]
Domains is x values 
Thus 
Domains : -5 , 3 , , 4

Range is all y values 
Range: 4 , -2, 4 , 3
4 0
3 years ago
What is 2.419 rounded to the nearest one?
Advocard [28]

Answer:

2

Step-by-step explanation:

4 0
3 years ago
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The sum of the digits of a 2-digit number is 11. If the digits are reversed, the number formed is 45 more than the original numb
jeka57 [31]
<h2>the original number is 38</h2>

Step-by-step explanation:

Let the two-digit number be 10t+u where t is the tens digit and u the units digit.

-------------------

EQUATION:

t+u = 11

10u+t = 10t+u + 45

-------------

Rearrange the equations:

t+u = 11

9t-9u = -45

-------------

Simplify:

 

t+u = 11

t-u = -5

---------

Add the equations to solve for "t":

2t = 6

t = 3

--------

Substitute to solve for "u":

3+u = 11

u = 8

6 0
4 years ago
C) Three yam tubers are chosen at random from 15 tubers of which 5 are spoilt. Find the probability that, of the three chosen tu
Dmitry_Shevchenko [17]

\displaystyle\\|\Omega|=\binom{15}{3}=\dfrac{15!}{3!12!}=\dfrac{13\cdot14\cdot15}{2\cdot3}=455

a)

\displaystyle\\|A|=\binom{10}{3}=\dfrac{10!}{3!7!}=\dfrac{8\cdot9\cdot10}{2\cdot3}=120\\\\P(A)=\dfrac{120}{455}=\dfrac{24}{91}\approx26.4\%

b)

\displaystyle\\|A|=\binom{5}{3}=\dfrac{5!}{3!2!}=\dfrac{4\cdot5}{2}=10\\\\P(A)=\dfrac{10}{455}=\dfrac{2}{91}\approx2.2\%

c)

\displaystyle\\|A|=\binom{10}{2}\cdot5=\dfrac{10!}{2!8!}\cdot5=\dfrac{9\cdot10}{2}\cdot5=225\\\\P(A)=\dfrac{225}{455}=\dfrac{45}{91}\approx49.5\%

d)

A - at least one is spoilt

A' - none is spoilt

P(A)=1-P(A')

We calculated P(A') in a).

Therefore

P(A)=1-\dfrac{24}{91}=\dfrac{67}{91}\approx73.6\%

7 0
2 years ago
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