Notes separated by a perfect fifth have a frequency ratio of 3:2.
The frequency of the note a perfect fifth below B3 will be
246.94×2/3 = 164.62667
The appropriate choice is ...
164.63 Hz
Answer:
a) 
b) n = 381
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

90% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
a. Assume that nothing is known about the percentage of computers with new operating systems. n = ?
When we do not know the proportion, we use
, which is when we are going to need the largest sample size.
The sample size is n when M = 0.01.






b. Assume that a recent survey suggests that 99% of computers use a new operating system. n = ?
Now we have that
. So






Rouding up
n = 381
y=-3x/2
because gradient =-3/2
and u must use formula (y-y1) = m(x-x1)
Answer:
Step-by-step explanation:
Givens
L = 4/5 m
w = 3/5 m
Formula
A = L * w
Solution
Area = 4/5 * 3/5
Area = (4 *3 ) / (5 * 5)
Area = 12/ 25 m^2
A) 65%
b) 68
26:40 as x:100
26/40 = x/100
Cross multiply
2600 = 40x
x = 65
———————
85% of 80
0.85 is the decimal equivalent of 85%
80 x 0.85 = 68