Volume of a quadrangular pyramid=(1/3)bh
b=base
h=height
b=area of the base=area of a square=8.4 ft * 8.4 ft=70.56 ft²
Pythagoras theorem:
hypotenuse²=leg₁² + leg₂²
data:
hypotenuse=9.6 ft
leg₁=height=h
leg₂=8.4 ft /2=4.2 ft
(9.6 ft)²= h² + (4.2 ft)²
92.16 ft²=h²+17.64 ft²
h²=92.16 ft²-17.64 ft²
h²=74.52 ft²
h=√(74.52 ft²)=8.63 ft.
Volume of this quadrangular pyramid=(1/3)(70.56 ft²)(8.63 ft)=202.9 ft³≈202.3 ft³
Answer: ≈202.3 ft³
Answer:
3
Step-by-step explanation:
In this expression, the first term is <em>2x</em>, then <em>4y, </em>then 8-2 (which simplifies to 6).
9514 1404 393
Answer:
40°
Step-by-step explanation:
Triangles QRS and QTS are congruent (HL), so the marked angles are also congruent:
3x +2 = 4x -4
6 = x
Then the total angle measure of angle RST is ...
(3x +2) +(4x -4) = 7x -2 = 7(6) -2 = 40 . . . degrees
m∠RST = 40°
Solve for p by simplifying both sides of the equation, then isolating the variable.
p=6
Answer:
803.84 in^3
Step-by-step explanation:
First of all we have to find the base area
base area = radius^2 x 3.14 = 8^2 x 3.14 = 64 x 3.14 = 200,96 in^2
the volume can be find with this formula:
V = (base area x height)/3
V = (200.96 x 12)/3 = 803.84 in^3
