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Leto [7]
3 years ago
6

What is the approximate circumrefernce circle with the redius of 8.5 meters

Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
6 0

The circumference of a circle is 2(3.14)r, and if 8.5 * 2 is 17, the answer will be 17*3.14.

An estimate is 51, and the actual answer is 53.38.

Fynjy0 [20]3 years ago
6 0

Answer:

C = 53.38 m

Step-by-step explanation:

The formula for circumference is

C = 2 * pi *r

we know the radius is 8.5  and we can approximate pi by 3.14

C = 2 * (3.14) * 8.5

C = 53.38 m

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iren2701 [21]

Answer:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

Step-by-step explanation:

Let's find the answer.

Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.

Equations:

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Eq. 2 : x1 + x2 + x3 = 6

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From eq. 1 : 1 ; 2 ; 5

From eq. 2 : 1 ; 1 ; 1

From eq. 3 : 4 ; 6 ; 5

So matrix A is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]

And the vector of vriables (X) is:

\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]

Now we can find the resulting vector (B) using the 'resulting values' from each equation:

\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

In conclusion, AX=B is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

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Hello
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