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3 years ago

How do I know if it's a function or not?

Mathematics

2 answers:

Effectus [21]3 years ago

5 0

In plain and short, a function has no x-coordinate Repeats, if there's an x-coordinate Repeat, then is not a function.

$\bf \begin{array}{ccll}
x&y\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
6&3\\
8&2\\
9&0\\
\stackrel{re peat}{11}&1\\
\stackrel{re peat}{11}&2
\end{array}$

Free_Kalibri [48]3 years ago

3 0

Your domain would be (6,8,9,11,11)
your range would be (3,2,0,1,2)
This is not a function because the domain 11 is paired with both the range of 1 and 2

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The ratio of boys to girls in math classes is 3.5. If there are 130 girls in these classes, how many boys must there be?

dsp73

Answer:

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

The ratio of boys and girls =3:5

Let

Number of boys=3x

Number of girls =5x

According to the question Numbers of girls=130

${:}\longrightarrow$ $\sf 5x=130$

Now interchange both sides and get x

${:}\longrightarrow$ $\sf x={\dfrac {130}{5}}$

${:}\longrightarrow$ $\sf x=26$

The number of boys=3x

=3×26=78

$\therefore$ Number of boys is 78.

4 0

2 years ago

Justify solution<br>-1/2(5x-8)=7<br>5x-8=-14<br>5x=-6<br>x=-6/5

Leona [35]

Answer:

solution is -6/5 because:

-1/2(5x-8)=7

-5x+8/2=7

-5x+8=7*2

-5x+8=14

-5x=14-8

-5x=6

x=-6/5

5 0

3 years ago

Encuentra el valor medio punto pendiente m=5 p(3,-2)

Tresset [83]

Answer:

y=5x−17

Step-by-step explanation:

8 0

2 years ago

Suppose you invested $1500 in an ac count that paid an annual of 3% compound monthly. How much would you have after 1 year?

Sati [7]

Answer:

1545.62

Step-by-step explanation:

The calculation of compound interests uses this formula:

Where A = total amount, P = principal or amount of money deposited, r = annual interest rate, n = number of times compounded per year and t = time in years.

So, if we plug-in the numbers of the problem we have:

Which gives us:

$A = 1500 * 1.0025^{12} = 1500 * 1.030416 = 1545.62$

For a grand total of 1,545.62 including capital and interests.

3 0

3 years ago

Triangle PQR has vertices at the following coordinates: P(0, 1), Q(3, 2), and R(5, -4). Determine whether or not triangle PQR is

ruslelena [56]

$PQ = \sqrt{(3-0)^2+(2-1)^2}= \sqrt{9+1}= \sqrt{10} \\ QR= \sqrt{(5-3)^2+(-4-2)^2}= \sqrt{4+36}= \sqrt{40} \\PR= \sqrt{(5-0)^2+(-4-1)^2}= \sqrt{25+25}= \sqrt{50}$

PR is the longest side.
The triangle will be right if
PQ² + QR² = PR²

PQ² + QR² = (√10)² + (√40)² = 10 + 40 = 50
PR² = (√50)² = 50
50=50 so, ΔPQR is <span>a right triangle.</span>

8 0

3 years ago

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