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Tom [10]
2 years ago
6

Working alone, it would take Shandra 45 minutes to mow the lawn. To mow the same lawn, also working alone, it would take Kelly 1

hour and 15 minutes. If they work together, the girls believe it will take them 1 hour to mow the lawn. Which best describes the reasonableness of their solution?
Mathematics
2 answers:
qaws [65]2 years ago
6 0
No! It would take them two hours. Seventy-five(an hour and fifteen minutes) plus sixty minutes would equals one thirty-five. Which is two hours.
Nadusha1986 [10]2 years ago
5 0

Given: Shandra can do the complete work in 45 minutes.

So, Shandra's 1-minute work = 1 / 45  and

Kelly can do the same complete work in 1 hour and 15 minutes = 75 minutes.

So, Kelly's 1-minute work = 1 / 75

Now, we shall calculate Shandra's and Kelly's 1-minute work

By both 1 minute work = (1/45) + (1 / 75) = 8 / 225

∵ 8 /225 Parts can be completed by both = in 1 minute

∴ Complete work (1) can be completed by both = 225 / 8 minutes

or,                                                                           = in 28 minutes and 7.5 second

Hence, the assumption taken by both was incorrect.

The best described time will be 28 minutes and 8 seconds.  

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allsm [11]

Here is your answer:


Move all terms with m to the left, all other terms to the right:


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3 years ago
SUppose the total cost C(x) to manufacture a quantity x of insecticide (in hundreds of liters) is given by
Hitman42 [59]

Answer:

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b) C(x) decreases in (8\,s, 10\,s).

Step-by-step explanation:

Let C(x) = x^{3}-27\cdot x^{2}+240\cdot x +850, where x is the quantity of insecticide, measured in hundreds of liters, and C(x) is the total manufacturing cost as a function of the quantity of the insecticide, measured in US dollars. A possible approach to determine which regions of C(x) are decreasing and increasing by means of the first derivative and graphing tools. The first derivative of the function is:

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Please notice that regions where C(x) is increasing has C'(x) > 0, whereas C'(x) < 0 when C(x) < 0.

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timofeeve [1]

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sin(2A) = sin(A+B) cos(A−B) + sin(A−B) cos(A+B)

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Pythagorean identity:

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Calculate time, solve for t

t = ln(A/P) / r

3 0
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