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Tom [10]
3 years ago
6

Working alone, it would take Shandra 45 minutes to mow the lawn. To mow the same lawn, also working alone, it would take Kelly 1

hour and 15 minutes. If they work together, the girls believe it will take them 1 hour to mow the lawn. Which best describes the reasonableness of their solution?
Mathematics
2 answers:
qaws [65]3 years ago
6 0
No! It would take them two hours. Seventy-five(an hour and fifteen minutes) plus sixty minutes would equals one thirty-five. Which is two hours.
Nadusha1986 [10]3 years ago
5 0

Given: Shandra can do the complete work in 45 minutes.

So, Shandra's 1-minute work = 1 / 45  and

Kelly can do the same complete work in 1 hour and 15 minutes = 75 minutes.

So, Kelly's 1-minute work = 1 / 75

Now, we shall calculate Shandra's and Kelly's 1-minute work

By both 1 minute work = (1/45) + (1 / 75) = 8 / 225

∵ 8 /225 Parts can be completed by both = in 1 minute

∴ Complete work (1) can be completed by both = 225 / 8 minutes

or,                                                                           = in 28 minutes and 7.5 second

Hence, the assumption taken by both was incorrect.

The best described time will be 28 minutes and 8 seconds.  

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Step-by-step explanation:

For this case we have the following distribution given:

X      1      2      7

P(X) 1/5  2/5   2/5

We need to begin finding the mean with this formula:

E(X) = \sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(X) =1 *\frac{1}{5} +2 *\frac{2}{5} +7*\frac{2}{5}= 3.8

Now we can find the second moment with this formula:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =1^2 *\frac{1}{5} +2^2 *\frac{2}{5} +7^2*\frac{2}{5}= 21.4

The variance would be given by:

Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96

And the deviation would be:

Sd(X) =\sqrt{6.96}= 2.638

7 0
3 years ago
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