All categories

2 years ago

Find the parallel line to 5y-15x=-20 that goes through the point (3,-6).

Mathematics

1 answer:

Shtirlitz [24]2 years ago

8 0

5y-15x=-20
5y=15x-20
y=3x-20/3
Slope = 3

Slope Intercept Form
y-y1=m(x-x1)
Therefore y-(-6)=3(x-3)
y+6=3x-9
y=3x-15

You might be interested in

A rectangle with a perimeter of 19m^2+2m-10 and a width of m^2 write an expression for the lenght

expeople1 [14]

Answer:

$8.5m^{2}+ m -5$

Step-by-step explanation:

Since perimeter, $P=19m^{2}+ 2m -10$ and we know that P=2(l+w) then $P=2(l+m^{2})=2l+2m^{2}$

The length will be $2l=19m^{2}+ 2m -10-2m^{2}=17m^{2}+ 2m -10$

Now $l=8.5m^{2}+ m -5$

6 0

3 years ago

Square root of 81 minus square root of negative 48 answer in a + bi form

galina1969 [7]

Answer:

9-6.92820323i Nothing else can be done.

Step-by-step explanation:

-48 is not a perfect square but 81 is a square. When you try to square -48 it comes to be 6.92820323i.

4 0

3 years ago

If sin x = 3/5, calculate tan x

ZanzabumX [31]

Answer:

tan ( x ) = ± 3 /4

Step-by-step explanation:

4 0

3 years ago

Help please! :(

Mekhanik [1.2K]

Answer:

5.51 meters

Step-by-step explanation:

3 0

3 years ago

A rectangular piece of metal is 25 in longer than it is wide. Squares with sides 5 in long are cut from the four corners and the

Licemer1 [7]

Answer:

The original length was 41 inches and the original width was 16 inches

Step-by-step explanation:

Let

x ----> the original length of the piece of metal

y ----> the original width of the piece of metal

we know that

When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box

The dimensions of the box are

$L=(x-10)\ in\\W=(y-10)\ in\\H=5\ in$

The volume of the box is equal to

$V=(x-10)(y-10)5$

$V=930\ in^3$

$930=(x-10)(y-10)5$

simplify

$186=(x-10)(y-10)$ -----> equation A

Remember that

The piece of metal is 25 in longer than it is wide

$x=y+25$ ----> equation B

substitute equation B in equation A

$186=(y+25-10)(y-10)$

solve for y

$186=(y+15)(y-10)\\186=y^2-10y+15y-150\\y^2+5y-336=0$

Solve the quadratic equation by graphing

using a graphing tool

The solution is y=16

see the attached figure

Find the value of x

$x=16+25=41$

therefore

The original length was 41 inches and the original width was 16 inches

3 0

3 years ago