What is a correct name for the polygon?

Mathematics

2 answers:

lions [1.4K]3 years ago

8 0

I believe your answer would be <span>d. BAEAB</span>

Karo-lina-s [1.5K]3 years ago

6 0

The answer is D,BAEAB,It makes more sense then the other options.

Hope this helps.

You might be interested in

The population of Mexico has been increasing at an annual rate of 1.7%. If the population was 100,350,000 in the year 2000, pred

Svetllana [295]

We can withdraw a equation to give mexico population

P = M.(1 + i)^t

So,

First of all, how many years passed? 2015 - 2000 = 15. Our time is 15, our annual rate is 1,7%, time to calc.

P = 100350000.(1 + 1,7%)^15

1,7% = 0,017

P = 100350000.(1 + 0,017)^15

P = 100350000.(1,017)^15

P = 100350000.1,2876988084901218382866596204289

P = 129220575,43198372647206629291004

Rounding

P = 129,220,575

8 0

2 years ago

Read 2 more answers

Because not all airline passengers show up for their reserved seat, an airline sells 125 tickets for a flight that holds only 12

melamori03 [73]

Answer:

98.75% probability that every passenger who shows up can take the flight

Step-by-step explanation:

For each passenger who show up, there are only two possible outcomes. Either they can take the flight, or they do not. The probability of a passenger taking the flight is independent from other passenger. So the binomial probability distribution is used to solve this question.

However, we are working with a large sample. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .