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3 years ago

What is the result when the number 40 is increased by 10%?

Mathematics

2 answers:

Pepsi [2]3 years ago

8 0

Answer:

Step-by-step explanation:

10 percent of 40 is 4 and if you raise it by 10 percent, you have to add 40 and 4 making 44.

You can also search up these answers or search up what is (whatever percent) of (whatever number)

Goshia [24]3 years ago

7 0

The answer is 44.

40 / 100 = 0,4 * 10 = 4 (10%)

40 + 4 = 44

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Use the Ratio Test to determine the convergence or divergence of the series. If the Ratio Test is inconclusive, determine the co

jeka57 [31]

Answer:

<h2>A. The series CONVERGES</h2>

Step-by-step explanation:

If $\sum a_n$ is a series, for the series to converge/diverge according to ratio test, the following conditions must be met.

$\lim_{n \to \infty} |\frac{a_n_+_1}{a_n}| = \rho$

If $\rho$ < 1, the series converges absolutely

If $\rho > 1$ , the series diverges

If $\rho = 1$ , the test fails.

Given the series $\sum\left\ {\infty} \atop {1} \right \frac{n^2}{5^n}$

To test for convergence or divergence using ratio test, we will use the condition above.

$a_n = \frac{n^2}{5^n} \\a_n_+_1 = \frac{(n+1)^2}{5^{n+1}}$

$\frac{a_n_+_1}{a_n} = \frac{{\frac{(n+1)^2}{5^{n+1}}}}{\frac{n^2}{5^n} }\\\\ \frac{a_n_+_1}{a_n} = {{\frac{(n+1)^2}{5^{n+1}} * \frac{5^n}{n^2}\$

$\frac{a_n_+_1}{a_n} = {{\frac{(n^2+2n+1)}{5^n*5^1}} * \frac{5^n}{n^2}\\$

aₙ₊₁/aₙ =

$\lim_{n \to \infty} |\frac{ n^2+2n+1}{5n^2}| \\\\Dividing\ through\ by \ n^2\\\\\lim_{n \to \infty} |\frac{ n^2/n^2+2n/n^2+1/n^2}{5n^2/n^2}|\\\\\lim_{n \to \infty} |\frac{1+2/n+1/n^2}{5}|\\\\$

note that any constant dividing infinity is equal to zero

$|\frac{1+2/\infty+1/\infty^2}{5}|\\\\$

$\frac{1+0+0}{5}\\ = 1/5$

$\rho = 1/5$

Since The limit of the sequence given is less than 1, hence the series converges.

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VikaD [51]

Sent a pic of the solution (s).

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3 years ago

What is the nearest dollar if it's 3.75?

Semenov [28]

$3.75 would be rounded up and changed to $4

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3 years ago

(t^-4)^-9t^2 <br><br> A)t^26<br> B)t^-26<br> C)t^38<br> D)t^-38

Arisa [49]

The relevant rules of exponents are
.. (t^a)^b = t^(a·b)
.. t^a·t^b = t^(a+b)

You have
.. (t^-4)^-9·t^2
.. = t^((-4)*(-9) +2)
.. = t^38 . . . . . . . . . . . selection C

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3 years ago

Find the indicated critical z value. Find zα/2 for α = 0.08

snow_lady [41]

Refer to the diagram shown below.
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Half the tail area is α/2 = 0.08/2 = 0.04.
The central area is 1 - 0.04 - 0.04 = 0.92.

From standard normal tables, obtain
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Answer: 1.75

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3 years ago