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REY [17]
3 years ago
15

If y = x - 6 were changed to y = x+8, how would the graph of the new function

Mathematics
1 answer:
antoniya [11.8K]3 years ago
7 0
The answer is D.) It would be shifted up
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I’m begging for help!! ASAP
kompoz [17]

This is an awful question.  They mean to say  the number of hours practicing <em>per week</em> (we'll call it h) varies inversely with the <em>time</em> (t) she runs her event.  Unless they mean to imply more practicing makes Tyler slower, in which case she should just get a pizza.

Inverse variation means the product is a constant, we'll call it k.

ht = k

When h = 1 hour t=6 minutes

(1)(6) = k

k = 6  (hour*minutes, but as long as we're consistent we don't need to sweat the unit.)

Decreasing her time by one minute means t = 6 - 1 = 5.  We solve for h.

ht = k

h = k/t = 6/5 = 1.2 hours

Answer: 1.2 hours, second choice

8 0
3 years ago
1. Tanner collected 360 cans and bottles while fundraising for his baseball team. This was 40% of what Reggie collected. How man
Inessa05 [86]
1. 360*0.40=144
so they said 40% reggie collected main mor than 40% collected so you need to do add like 360+144=504
the answer 504

2. you need to do new to old
the new is 15 old is 799
799-15=784x100
the high number is 799
so you need to do 799 divided by 100=7.99
now 784 divided by 7.99=98.12
the answer is 98.12

3 0
3 years ago
Mixed number eqivalent to 51/5
mafiozo [28]
51/5 is equivalent to 10 and 1/5.

6 0
3 years ago
Richard has just been given an l0-question multiple-choice quiz in his history class. Each question has five answers, of which o
myrzilka [38]

Answer:

a) 0.0000001024 probability that he will answer all questions correctly.

b) 0.1074 = 10.74% probability that he will answer all questions incorrectly

c) 0.8926 = 89.26% probability that he will answer at least one of the questions correctly.

d) 0.0328 = 3.28% probability that Richard will answer at least half the questions correctly

Step-by-step explanation:

For each question, there are only two possible outcomes. Either he answers it correctly, or he does not. The probability of answering a question correctly is independent of any other question. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Each question has five answers, of which only one is correct

This means that the probability of correctly answering a question guessing is p = \frac{1}{5} = 0.2

10 questions.

This means that n = 10

A) What is the probability that he will answer all questions correctly?

This is P(X = 10)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{10,10}.(0.2)^{10}.(0.8)^{0} = 0.0000001024

0.0000001024 probability that he will answer all questions correctly.

B) What is the probability that he will answer all questions incorrectly?

None correctly, so P(X = 0)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.2)^{0}.(0.8)^{10} = 0.1074

0.1074 = 10.74% probability that he will answer all questions incorrectly

C) What is the probability that he will answer at least one of the questions correctly?

This is

P(X \geq 1) = 1 - P(X = 0)

Since P(X = 0) = 0.1074, from item b.

P(X \geq 1) = 1 - 0.1074 = 0.8926

0.8926 = 89.26% probability that he will answer at least one of the questions correctly.

D) What is the probability that Richard will answer at least half the questions correctly?

This is

P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{10,5}.(0.2)^{5}.(0.8)^{5} = 0.0264

P(X = 6) = C_{10,6}.(0.2)^{6}.(0.8)^{4} = 0.0055

P(X = 7) = C_{10,7}.(0.2)^{7}.(0.8)^{3} = 0.0008

P(X = 8) = C_{10,8}.(0.2)^{8}.(0.8)^{2} = 0.0001

P(X = 9) = C_{10,9}.(0.2)^{9}.(0.8)^{1} \approx 0

P(X = 10) = C_{10,10}.(0.2)^{10}.(0.8)^{0} \approx 0

So

P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.0264 + 0.0055 + 0.0008 + 0.0001 + 0 + 0 = 0.0328

0.0328 = 3.28% probability that Richard will answer at least half the questions correctly

8 0
3 years ago
Quickly please I have like 7 minutes of class
Vinvika [58]

Answer:

the question is blurry take a picture again

Step-by-step explanation:

4 0
3 years ago
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