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dimaraw [331]
3 years ago
11

Emily is a very good student. She is more likely to attend class than to miss class. Which could be t.he probability that she mi

sses class tomorrow?
a. -0.4
b. 0.1
c. 0.7
d. 1.2
(PLEASE EXPLAIN HOW YOU RECEIVED YOUR ANSWER)
Mathematics
1 answer:
evablogger [386]3 years ago
5 0
The correct answer is 0.1. C and D can automatically be eliminated because Emily is a good student who is likely to attend school. This leaves A and C, but A can be eliminated because there is still a possibility Emily will miss class.
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What is the common difference for the arithmetic sequence 4.7,6,7.3,8.6,9.9
mylen [45]

Answer: 1.3

Step-by-step explanation:

If u subtract 6-4.7 u will get 1.3 and you can also do it for all and u will still get the same answer

6 0
3 years ago
In the United States nearly 8 x 10^9 text messages are sent everymonth About how many text messages is this! Find the primefacto
iris [78.8K]
8\times10^9=2^{12}\times5^9

1) Since in the USA 8 x 10 ^9 messages are sent every month, that means that approximately 8 billion messages are sent.

2) We can Prime factorize it:

Note that on the right side we've picked only prime numbers. In this case, 2 and 5.

So we can rewrite 8 x 10^9 as prime factors.

8\times10^9=2^{12}\times5^9

3) Hence, the answer is:

8\times10^9=2^{12}\times5^9

7 0
1 year ago
The present age of Madison’s mother is 3 times that of Madison. After 614 years, the sum of their age will be 5334 years. Find t
Neporo4naja [7]

The present age of Madison is <u>1027 years</u> and that of his mother is <u>3080 years</u> (rounded off to nearest whole numbers), solved using the linear equation in one variable: <u>(x + 614) + (3x + 614) = 5334</u>, where x represents the present age of Madison.

<h3>What are linear equations in one variable?</h3>

Linear equations in one variable are the linear relationship between two algebraic expressions not involving more than one variable throughout the equation.

<h3>How to solve the question?</h3>

In the question, we are informed that the present age of Maison's mother is 3 times that of Madison. After 614 years, the sum of their age will be 5334 years.

We are asked to determine their present ages.


We assume the present age of Madison to be x years.

Therefore, the present age of Madison's mother = 3x years {3 times that of Madison}.

Now, after 614 years, both of their ages will increase by 614 years.

Therefore, age of Madison after 614 years = x + 614 {Present + 614}.

Age of Madison's mother = 3x + 614 {Present + 614}.

We are given that after 614 years, the sum of their ages will be 5334.

This can be represented by the linear equation in one variable:

(x + 614) + (3x + 614) = 5334

This linear equation in one variable can be simplified and solved in the following way:

or, 4x + 1228 = 5334 {Simplifying},

or, 4x + 1228 - 1228 = 5334 - 1228 {Subtracting 1228 from both sides}

or, 4x = 4106 {Simplifying}

or, 4x/4 = 4106/4 {Dividing both sides by 4},

or, x = 1026.5 {Simplifying}.

Therefore, the present age of Madison = x = 1026.5 = 1027 years (nearest whole number).

The present age of Madison's mother = 3x = 3*1026.5 = 3079.5 = 3080 years (nearest whole number).

Learn more about linear equations in one variable at

brainly.com/question/185288

#SPJ2

7 0
2 years ago
Read 2 more answers
What is the approximate lateral surface area of the cylinder?<br> 9 cm<br> 2 cm
miss Akunina [59]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Find the equation of the tangent line at the point where the curve crosses itself. x = t^3-6t, y = t^2.
Sphinxa [80]

Here is the solution for this specific problem:

<span>Based from the graph, the curve will intersect itself at the y-axis, i.e. x = 0. </span><span>

</span><span>t^3 - 6t = 0 </span><span>
<span>t(t^2 - 6) = 0 </span>
<span>t = 0 or t = ± √6 </span>

<span>dx/dt = 3t^2 - 6 </span>
<span>dy/dt = 2t </span>

<span>dy/dx = 2t/(3t^2 - 6) </span>

<span>@ t = 0, dy/dx = 0. </span>
<span>x = 0, y = 0 </span>

<span>y = 0 </span>

<span>@ t = √6, dy/dx = 2√6/12 = √6/6 </span>
<span>x = 0, y = 6 </span>

<span>y - 6 = (√6/6) x </span>
<span>y = (√6/6)x + 6 </span>

<span>@ t = -√6, dy/dx = -2√6/12 = -√6/6 </span>
<span>x = 0, y = 6 </span>

<span>y - 6 = (-√6/6) x </span>
y = (-√6/6)x + 6</span>

So the equations of the tangent line at the point where the curve crosses itself are: <span>y = (√6/6)x + 6 and </span>y = (-√6/6)x + 6. I am hoping that these answers have satisfied your queries and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.

4 0
4 years ago
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