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seraphim [82]
1 year ago
14

In the United States nearly 8 x 10^9 text messages are sent everymonth About how many text messages is this! Find the primefacto

rization of this number and write the result using exponents.
Mathematics
1 answer:
iris [78.8K]1 year ago
7 0
8\times10^9=2^{12}\times5^9

1) Since in the USA 8 x 10 ^9 messages are sent every month, that means that approximately 8 billion messages are sent.

2) We can Prime factorize it:

Note that on the right side we've picked only prime numbers. In this case, 2 and 5.

So we can rewrite 8 x 10^9 as prime factors.

8\times10^9=2^{12}\times5^9

3) Hence, the answer is:

8\times10^9=2^{12}\times5^9

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Answer:

Step-by-step explanation:

x^2 - x - 30

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4 years ago
Solve the system by substitution.<br> y = -7x+ 3<br> y = -8x
QveST [7]

Answer:

x = -3, y = 24

Step-by-step explanation:

y=−7x+3;y=−8x

Step: Solve y=−7x+3 for y:

y=−7x+3

Step: Substitute−7x+3 for y in y=−8x:

y=−8x

−7x+3=−8x

−7x+3+8x=−8x+8x(Add 8x to both sides)

x+3=0

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x=−3

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y=−7x+3

y=(−7)(−3)+3

y=24(Simplify both sides of the equation)

7 0
3 years ago
Read 2 more answers
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xenn [34]

If you raise -4 to the power of 2, you will get -4x-4. So (-4)^2 is the answer.

5 0
4 years ago
1 point) As reported in "Runner's World" magazine, the times of the finishers in the New York City 10 km run are normally distri
BigorU [14]

Answer:

(a) E (X) = 61 and SD (X) = 9

(b) E (Z) = 0 and SD (Z) = 1

Step-by-step explanation:

The time of the finishers in the New York City 10 km run are normally distributed with a mean,<em>μ</em> = 61 minutes and a standard deviation, <em>σ</em> = 9 minutes.

(a)

The random variable <em>X</em> is defined as the finishing time for the finishers.

Then the expected value of <em>X</em> is:

<em>E </em>(<em>X</em>) = 61 minutes

The variance of the random variable <em>X</em> is:

<em>V</em> (<em>X</em>) = (9 minutes)²

Then the standard deviation of the random variable <em>X</em> is:

<em>SD</em> (<em>X</em>) = 9 minutes

(b)

The random variable <em>Z</em> is the standardized form of the random variable <em>X</em>.

It is defined as:Z=\frac{X-\mu}{\sigma}

Compute the expected value of <em>Z</em> as follows:

E(Z)=E[\frac{X-\mu}{\sigma}]\\=\frac{E(X)-\mu}{\sigma}\\=\frac{61-61}{9}\\=0

The mean of <em>Z</em> is 0.

Compute the variance of <em>Z</em> as follows:

V(Z)=V[\frac{X-\mu}{\sigma}]\\=\frac{V(X)+V(\mu)}{\sigma^{2}}\\=\frac{V(X)}{\sigma^{2}}\\=\frac{9^{2}}{9^{2}}\\=1

The variance of <em>Z</em> is 1.

So the standard deviation is 1.

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3 years ago
A bar graphs shows that sports books received 9 votes. If the scale is 0 to 20 by twos , where should the bar end for the sports
olya-2409 [2.1K]
A little past the 8.
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