For the inverse variation equation p = StartFraction 8 Over V EndFraction, what is the value of V when p = one-half?

Mathematics

1 answer:

likoan [24]2 years ago

3 0

Answer:

V=16

Step-by-step explanation:

We are given that an inverse variation

$p=\frac{8}{V}$

We have to find the value of V when p=1/2

To find the value of V we will substitute the value of p

Substitute the value of p

Then, we get

$\frac{1}{2}=\frac{8}{V}$

$\frac{V}{2}=8$

Using multiplication property of equality

$V=8\times 2$

Using multiplication property of equality

$V=16$

Hence, the value of V=16

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LA = 25√2π,

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Step-by-step explanation:

We need to determine the height here, as it is not given, and is quite important to us. The height is a perpendicular line segment to the radius, hence forming a 45 - 45 - 90 degree triangle as you can see. Therefore, by " Converse to Base Angles Theorem " the height should be equal in length to the radius,

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Now knowing the height, let's begin by calculating the base area. By it's name, we have to find the area of the base. As it is a circle, let us apply the formula " πr^2 "

$\pi r^2\\= \pi ( 5 )^2\\= 25\pi$ - Base Area = 25π

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The lateral area is simply the surface area excluding the base area, the surface area having a formula of " πr^2 + πrl. " Thus, the lateral area can be calculated through the formula " πrl, " but as we are not given the slant height ( l ) we have to use another formula, $l= \sqrt{r^2+h^2}$ -