Give the angle pair name to justify your work equation setup and solve for x.<br> 6x

(-7x∧5 + 14 - 2x) + (10x∧4 + 7x + 5x∧5)

Maslowich

$-7x^5 + 5x^5 +10x^4 -2x + 7x + 14= -2x^5 +10x^4 +5x + 14$

Your answer is $-2x^5 +10x^4 +5x + 14$

7 0

4 years ago

Plzzzz help asap lost ten u gain it asap

faltersainse [42]

Your unit cost will be $0.11 :)

7 0

3 years ago

Which postulate or theorem proves that these two triangles are

Aleksandr-060686 [28]

Answer: O AAS Congruence Theorem is your answer

Step-by-step explanation: plz give brainliest

4 0

3 years ago

The function f(x) is represented by the table below. What are the corresponding values of g(x) for the transformation g(x) = 6f(

g100num [7]

Answer:

Given: The transformation g(x) =6f(x) ......[1]

To find the corresponding values of g(x) for the given transformation.

At x = -7, f(x) = 8

then,

By substituting the value of f(x) = 8 in [1] we have

$g(x) = 6 \cdot 8 =48$

Similarly,

For x= -3 , f(x) = 3, then

By substituting the value of f(x) = 3 in [1] we have

$g(x) = 6 \cdot 3 =18$

For x= 0, f(x) = -1 , then

By substituting the value of f(x) = -1 in [1] we have

$g(x) = 6 \cdot -1 =-6$

For x= 2, f(x) = 7, then

By substituting the value of f(x) = 7 in [1] we have

$g(x) = 6 \cdot 7=42$

For x= 10, f(x) = 5, then

By substituting the value of f(x) = 5 in [1] we have

$g(x) = 6 \cdot 5=30$

Therefore ; we have the corresponding values of g(x) as shown below;

x f(x) g(x)

-7 8 48

-3 3 18

0 -1 -6

2 7 42

10 5 30

5 0

4 years ago

Read 2 more answers

The accompanying data on x = current density (mA/cm2) and y = rate of deposition (m/min)μ appeared in a recent study.

gtnhenbr [62]

Answer:

a) $r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857$

The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables

b) $m=\frac{64.5}{2000}=0.03225$

Now we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{200}{4}=50$

$\bar y= \frac{\sum y_i}{n}=\frac{5.37}{4}=1.3425$

$b=\bar y -m \bar x=1.3425-(0.03225*50)=-0.27$

So the line would be given by:

$y=0.3225 x -0.27$

Step-by-step explanation:

Part a

The correlation coeffcient is given by this formula:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

For our case we have this:

n=4 $\sum x = 200, \sum y = 5.37, \sum xy = 333, \sum x^2 =12000, \sum y^2 =9.3501$

$r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857$

The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables

Part b

$m=\frac{S_{xy}}{S_{xx}}$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=12000-\frac{200^2}{4}=2000$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=333-\frac{200*5.37}{4}=64.5$

And the slope would be:

$m=\frac{64.5}{2000}=0.03225$

Now we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{200}{4}=50$

$\bar y= \frac{\sum y_i}{n}=\frac{5.37}{4}=1.3425$

And we can find the intercept using this:

$b=\bar y -m \bar x=1.3425-(0.03225*50)=-0.27$

So the line would be given by:

$y=0.3225 x -0.27$

4 0

3 years ago

Give the angle pair name to justify your work equation setup and solve for x. 6x - 24 2x + 12°