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denis23 [38]
3 years ago
11

The mole fraction of NaCl in an aqueous solution is 0.132. How many moles of water are present in 1 mole of this solution?

Chemistry
2 answers:
SOVA2 [1]3 years ago
7 0
You could look at it this way.
1 mole of solution = 0.132 of NaCl + x
1 - 0.132 = 0.868 mols of water.

answer: 0.868 <<<< answer


strojnjashka [21]3 years ago
4 0

Answer: The number of moles of water in the solution is 0.868 mole.

Explanation:

  • The summation of mole fractions of different components in solution is equal 1.0.
  • If a solution composed of different components (a, b, c, d, ...., n) and each component has its mole fraction (Xa, Xb, Xc, Xd, ......,Xn) then Xa + Xb + Xc + Xd + ... + Xn = 1.0
  • For the mentioned NaCl solution; the solution composed of NaCl and water: XNaCl + XH2O = 1.0
  • Also, it is important to define the mole fraction: XNaCl = nNaCl/ntotal and ntotal = nNaCl + nwater; where n id the number of mole (n = mass/molar mass)
  • XNaCl + XH2O = 1.0 and XNaCl = 0.132
  • then Xwater = 1.0 - 0.132 = 0.868
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Slav-nsk [51]

Answer:

7.28 mol Na2SO4

Explanation:

Since it is already in moles, all we have to do is use a molar ratio

A molar ratio is the proportions of reactants and products using the balanced equation. When writing a mole ratio, the given information must cross out with the right thing.

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5 0
3 years ago
Chromium metal is plated onto a car bumper at a current of 10.0 amperes for 100 seconds. The plating bath contains chromium in t
Phoenix [80]

Answer:

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Explanation:

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Faraday's first law of electrolysis states that

The mass of the substance (m) of a given substance deposited at an electrode is directly proportional to the quantity of electricity or charge (Q) passed

m = nQ

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n = electrochemical constant

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1 moles = molarmass = Faraday's constant (96500C)

Molar mass = Faraday's constant (96500C)

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6 0
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