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3 years ago

When talking about volume, milliliters is used for

Chemistry

2 answers:

Flura [38]3 years ago

7 0

Answer:

liquid

Explanation:

C, hope this helps

Tema [17]3 years ago

3 0

It’s Liquids big dawg

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1. The Tyndall Effect is most useful for distinguishing between: *

Yuki888 [10]

Answer:

a colloid and a solution

Explanation:

When solute particles completely dissolve in a solvent, a true solution is formed. The solute particles in this case are so little that they can not be seen with naked eyes. A true solution does not scatter rays of light.

In a false solution, the solute particles are larger than the solute particles in true solutions but are not large enough to be seen with naked eyes. False solutions scatter rays of light. False solutions are also called colloids.

The major difference between a solution and a colloid is that colloids scatter light rays (Tyndall effect) while a true solution does not scatter light rays.

5 0

3 years ago

How many moles of Li3N will be created using 0.24 moles of Li in the given reaction? 6Li + N2 2Li3N

andreyandreev [35.5K]

6 Li + N2 = 2 Li3N

6 moles Li ---------> 2 moles Li3N
0.24 moles Li ------> ?

moles Li3N = 0.24 * 2 / 6

= 0.48 / 6

= 0.08 moles of li3N

hope this helps!.

7 0

3 years ago

Read 2 more answers

Given the half‑reactions and their respective standard reduction potentials 1. Cr 3 + + e − ⟶ Cr 2 + E ∘ 1 = − 0.407 V 2. Cr 2 +

Licemer1 [7]

Answer:

The standard reduction potential for the reduction half‑reaction of Cr(III) to Cr(s) is -0.744 V

Explanation:

Here we have

1. Cr³⁺ + e − ⟶ Cr²⁺ E⁰₁ = − 0.407 V

2. Cr²⁺ + 2 e − ⟶ Cr ( s ) E⁰₂ = − 0.913 V

To solve the question, we convert, the E⁰ values to ΔG as follows

ΔG₁ = n·F·E⁰₁ and ΔG₂ = n·F·E⁰₂

Where:

F = Faraday's constant in calories

n = Number of e⁻

ΔG₁ = Gibbs free energy for the first reaction

ΔG₂ = Gibbs free energy for the second half reaction

E⁰₁ = Reduction potential for the first half reaction

E⁰₂ = Reduction potential for the second half reaction

∴ ΔG₁ = 1 × F × − 0.407 V

ΔG₂ = 2 × F × − 0.913 V

ΔG₁ + ΔG₂ = F × -2.233 V which gives

ΔG = n × F × ΔE⁰ = F × -2.233 V

Where n = total number of electrons ⇒ 1·e⁻ + 2·e⁻ = 3·e⁻ = 3 electrons

We have, 3 × F × ΔE⁰ = F × -2.233 V

Which gives ΔE⁰ = -2.233 V /3 = -0.744 V.

7 0

3 years ago

Connect them please, dont guess ill give brainiest to the FIRST answer + 29 points

Brut [27]

Answer:

I cant see it sorry

Explanation:

Post another one

5 0

3 years ago

A heparin drip (IV) has been ordered that contains 10,000 units of heparin in 1000ml of D5W (5% dextrose in water). The drip is

cluponka [151]

Answer:

12,000 units of heparin are received by patient in 24 hours.

Explanation:

10,000 units of heparin in 1000ml of D5W.

Units of heparin in 1 mL = $\frac{10,000}{1000}=10 units$

Rate at heparin drip set at = 50 ml/hour

Units of heparin in 50 ml of solution = $50\teimes 10 units =500 units$

500 units of heparin are received by patient in an every hour.So, in 24 hours patient will receive:

$500units\times 24 = 12,000 units$ of heparin

12,000 units of heparin are received by patient in 24 hours.

5 0

3 years ago