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xenn [34]
3 years ago
15

My question today is : The reaction of 11.9g go CHCl3 with excess chlorine produced 10.2g of CCl4, carbon tetrachloride. What is

the percent yield
Chemistry
1 answer:
Helga [31]3 years ago
5 0

Answer:

66.7%

Explanation:

Step 1: Write the balanced equation

CHCl₃ + Cl₂ ⇒ CCl₄ + HCl

Step 2: Calculate the theoretical yield of CCl₄ from 11.9 g of CHCl₃

According to the balanced equation, the mass ratio of CHCl₃ to CCl₄ is 119.38:153.82.

11.9 g CHCl₃ × 153.82 g CCl₄/119.38 g CHCl₃ = 15.3 g CCl₄

Step 3: Calculate the percent yield of CCl₄

Given the experimental yield of CCl₄ is 10.2 g, we can calculate the percent yield using the following expression.

%yield = (exp yield/theo yield) × 100%

%yield = (10.2 g/15.3 g) × 100% = 66.7%

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The following structure depicts three C atoms, two Br atoms, and eight H atoms,
Darya [45]

Answer: False

Explanation: There are four carbon atoms , eight hydrogen atoms and two Bromine atoms.

As the carbon forms four covalent bonds, every carbon must have four bonds and thus the formula of the compound is BrCH_2-CH(Br)-CH_2-CH_3.

IUPAC name of the compound is 1,2 di-bromobutane. As the carbon chain is 4 atoms long the word used is but and all the bonds are single bonds, thus the suffix used is ane.

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2 years ago
Use the picture below to answer the question. Comparing Wave A (blue) to Wave B (red), Wave B has a
fenix001 [56]

Answer: B longer wave

Explanation:

because

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2 years ago
HELP. NO FAKE ANSWERS. I WILL REPORT. I AM CONFUSED AND NEED HELP. FILL IN THE NOT FILLED BOXES POR FAVOR.
SCORPION-xisa [38]
Question #1
Potasium hydroxide (known)
 volume used is 25 ml 
Molarity (concentration) = 0.150 M
Moles of KOH used 
           0.150 × 25/1000 = 0.00375 moles
Sulfuric acid (H2SO4) 
volume used = 15.0 ml
unknown concentration
The equation for the reaction is
2KOH (aq)+ H2SO4(aq) = K2SO4(aq) + 2H2O(l) 
Thus, the Mole ratio of KOH to H2SO4 is 2:1
Therefore, moles of H2SO4 used will be;
      0.00375 × 1/2 = 0.001875 moles
Acid (sulfuric acid)  concentration
    0.001875 moles × 1000/15  
        = 0.125 M

Question #2
Hydrogen bromide (acid)
Volume used = 30 ml
Concentration is 0.250 M
Moles of HBr used;
      0.25 × 30/1000
        =  0.0075 moles 
Sodium Hydroxide (base)
Volume used 20 ml 
Concentration (unknown)
The equation for the reaction is 
NaOH + HBr = NaBr + H2O
The mole ratio of NaOH : HBr   is 1 : 1
Therefore, moles of NaOH used;
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NaOH concentration will be 
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7 0
3 years ago
Write down examples of some natural acids and natural bases. Also write use of them.
trasher [3.6K]

Answer:

Formic acid, citric acid, Oxalic acid, washing soda, baking soda, etc. can be some examples of natural acids and natural bases. They both have domestic, industrial, and various other purposes.

Explanation:

<h3><u>NATURAL ACIDS</u>:</h3>

There are lots of natural acids present in our nature. Some of them are the following:

> <u>Formic acid</u>

 USE: It is used in the stimulation of oil and gas wells as it is less reactive towards the metal.

> <u>Citric acid</u>

 USE: It is considered as the best rust remover as it doesn't harm the metal just remove the rust.

> <u>Oxalic acid</u>

USE: It easily remove iron and ink stains and that's why it is used as an acid rinsing material in Laundries.

<h3><u>NATURAL BASES</u>:</h3>

There is a variety of natural base found in our nature which founds a lot of uses in day to day life. some of them are the following:

> <u>Washing soda</u>

USE: It is used in commercial detergent mixture to treat hard water.

> <u>Baking soda</u>

USE: It is the best rising agent used mostly in cooking and for domestic purposes like removing stains, etc..

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3 years ago
Light bending as it passes through a rain drop is an example of Transmission Diffraction Refraction Reflection
Yuliya22 [10]
The answer would be the third one listed, Refraction
4 0
3 years ago
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