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Svet_ta [14]
2 years ago
15

How many grams of ammonium chloride (NH4Cl) would be required to make a saturated solution in 1000 grams of water at 50 degrees

Celsius?
0 degrees Celsius - 90 g/100 mL
10 degrees Celsius - 70 g/100 mL
20 degree Celsius - 55 g/100 mL
30 degree Celsius - 45 g/100 mL
40 degrees Celsius - 35 g/100 mL
50 degrees Celsius - 29 g/100 mL
Chemistry
1 answer:
Pavel [41]2 years ago
3 0
<span>Since,
1000 grams of water = 1000 mL of water</span><span>
So, 
At any of the given temperature:
</span>1000 mL = 10 x 100 mL
<span>
moles of NH4Cl = 53.5/53.49
                          = 1.0 m
                          = 1.0 mol/Kg
Delta T = 2 x 1.86 x 1.0
             = 3.72 c
             = - 3.72 °C</span>
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Calculate δs∘rxn for the reaction2no(g) o2(g)→2no2(g)express your answer to one decimal place and include the appropriate units
Anna35 [415]

The δs∘rxn  for the reaction 2NO(g) + O_{2} → 2NO_{2} (g) will be -146 J/K.

Entropy would be a measurable physical characteristic and a scientific notion that is frequently connected to a condition of disorder, unpredictability, or uncertainty.

Entropy would be a measurement of the system's unpredictability or disorder. The entropy increases as randomness do. It has broad properties as well as a state function. It has the unit JK^{-1} mol^{-1}.

Entropy of the reaction can be calculated by the reaction.

ΔS^{0} rxn = 2 mol × S^{0} (NO_{2} (g) - 2 mol × S^{0} NO (g) - 1 mol × S^{0} (O_{2} )

ΔS^{0} rxn  = 2 mol × 240 J/mol.K - 2 mol × 210 J/mol.K-1 mol  ×205.2 J/mol.K

ΔS^{0} rxn  = -146.8 J/K

Therefore, the δs∘rxn  for the reaction 2NO(g) + O_{2} → 2NO_{2} (g) will be -146 J/K.

To know more about reaction

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4 0
1 year ago
Question 5(Multiple Choice Worth 3 points)
Travka [436]

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What volume of water is required to prepare 0.1 M H3PO4 from 100 ml of 0.5 M solution?
ExtremeBDS [4]

Answer: A volume of 500 mL water is required to prepare 0.1 M H_{3}PO_{4} from 100 ml of 0.5 M solution.

Explanation:

Given: M_{1} = 0.1 M,    V_{1} = ?

M_{2} = 0.5 M,       V_{2} = 100 mL

Formula used to calculate the volume of water is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\0.1 M \times V_{1} = 0.5 M \times 100 mL\\V_{1} = 500 mL

Thus, we can conclude that a volume of 500 mL water is required to prepare 0.1 M H_{3}PO_{4} from 100 ml of 0.5 M solution.

7 0
3 years ago
Calculation of Molar Ratios of Conjugate Base to Weak Acid from pH For a weak acid with a pKa of 6.0, calculate the ratio of con
Free_Kalibri [48]

Explanation:

According to the Handerson equation,  

          pH = pK_{a} + log \frac{\text{salt}}{\text{acid}}

or,      pH = pK_{a} + log \frac{\text{conjugate base}}{\text{acid}}

Putting the given values into the above equation as follows.

     pH = pK_{a} + log \frac{\text{conjugate base}}{\text{acid}}

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or,      \frac{\text{conjugate base}}{\text{acid}} = 10^{-1.0}

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7 0
2 years ago
Will mark Brainlest ( molecular weight of ammonium sulphate)<br>step by step​
Bond [772]

Answer:

132 amu

Explanation:

ammonium sulphate is (NH_4)_{2} SO_4

to calculate molecular weight we need

atomic weight of the element of the compound

here ammonium sulphate is formed by two elements

2 nitrogen , 8 hydrogen , 1 sulphur amd 4 oxygen

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so lets calculate molecular weight of ammonium sulphate

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132 amu

3 0
3 years ago
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