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Svet_ta [14]
2 years ago
15

How many grams of ammonium chloride (NH4Cl) would be required to make a saturated solution in 1000 grams of water at 50 degrees

Celsius?
0 degrees Celsius - 90 g/100 mL
10 degrees Celsius - 70 g/100 mL
20 degree Celsius - 55 g/100 mL
30 degree Celsius - 45 g/100 mL
40 degrees Celsius - 35 g/100 mL
50 degrees Celsius - 29 g/100 mL
Chemistry
1 answer:
Pavel [41]2 years ago
3 0
<span>Since,
1000 grams of water = 1000 mL of water</span><span>
So, 
At any of the given temperature:
</span>1000 mL = 10 x 100 mL
<span>
moles of NH4Cl = 53.5/53.49
                          = 1.0 m
                          = 1.0 mol/Kg
Delta T = 2 x 1.86 x 1.0
             = 3.72 c
             = - 3.72 °C</span>
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Blackmail threat of informational disclosure is an example of which threat category?
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6 0
3 years ago
Find the length of time required for the total pressure in a system containing N2O5 at an initial pressure of 0.110 atm to rise
USPshnik [31]

Answer:

t = 37.1 s

Explanation:

The equation for the reaction is given as;

                  2 N2O5(g)  --> 4 NO2 + O2

Initial:          0.110                  -             -

change:        -2x                  +4x        +x

Final:          0.110 - 2x           +4x        +x

But final = 0.150atm;

0.110 - 2x    +  4x   +  x = 0.150 atm

3x = 0.150 - 0.110

x = 0.0133 atm

Pressure in reactant side;

0.110 - 2x

0.110 - 2 (0.0133) = 0.0834 atm

The integral rate law expression is given as;

ln ( [A] / [Ao] ) = -kt

k =  rate constant = 7.48*10^-3*s-1

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upon solving, t = 37.1 s

3 0
3 years ago
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